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emmainna [20.7K]
3 years ago
7

5. Harrison claims that waves travel faster when the particles within the medium are farther apart. Is Harrison correct?

Physics
1 answer:
andrew11 [14]3 years ago
5 0

Answer:

सं देश भर भर में नौ महिना अघिदेखि महिना अघिदेखि नै जातीय आधारमा प्रान्त पुगें र नेपाली जनताको लागि फरक छ तर त्यो पनि पाँचै वर्षमा धरासायी भयो पाँचै वर्षमा धरासायी भयो भने हेर्न त्यो पनि हो र स्वार्थी हुन्छ भन्थे यो मेरो पहिलो मृत्यु भएको हो। छ। यो म भने त्यो प्रेम कति

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Consider the medium of air as defined by the use of radio frequency. What made some of the early standards so slow compared to t
Tanzania [10]

Answer:

Explanation:

Earliest standards were dependent on a single frequency/channel to both send and receive. This shared medium creates the same problem as half-duplex coax cable. Because receivers had to wait for the signal before sending a response, this reduced the overall bandwidth.

Other factors affect wireless signal propagation, too, including RF interference, antenna choice, and obstacles such as walls, trees, and even weather (precipitation, for example).

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4 years ago
A 0.453 kg pendulum bob passes through the lowest part of its path at a speed of 2.58 m/s. What is the tension in the pendulum c
harkovskaia [24]

Answer with Explanation:

Mass of pendulum bob, m=0.453 kg

Speed, v_1=2.58 m/s

a.r=75.1 cm=75.1\times 10^{-2}m=0.751 m

1cm=10^{-2} m

Tension in the pendulum cable is given  by

Tension=Centripetal force+force due to gravity

T=\frac{mv^2}{r}+mg

Where g=9.8 m/s^2

Substitute the values

T=\frac{0.453(2.58)^2}{75.1\times 10^{-2}}+0.453\times 9.8

T=8.45 N

b.When the pendulum reaches its highest point,then

Final velocity, v_2=0

According to law of conservation of energy

mgh_1+\frac{1}{2}mv^2_1=mgh_2+\frac{1}{2}mv^2_2

gh_1+\frac{1}{2}v^2_1=gh_2+\frac{1}{2}v^2_2

h_1=0

Substitute the values

9.8\times 0+\frac{1}{2}(2.58)^2=9.8\times h_2+\frac{1}{2}(0)^2

3.3282=9.8h_2

h_2=\frac{3.3282}{9.8}=0.34 m

The angle mad  by cable with the vertical=cos\theta=\frac{0.751-0.34}{0.751}=0.55

\theta=cos^{-1}(0.55)=56.6^{\circ}

c.When the pendulum reaches at highest point then

Acceleration, a=0

Therefore, the tension  in the pendulum cable

T=mgcos\theta

Substitute the values

T=0.453\times 9.8cos56.6

T=2.4 N

8 0
4 years ago
A long solenoid, of radius a, is driven by an alternating current, so that the field inside is sinusoidal: B(t) = B0 cos(ωt) ˆz.
Alexxandr [17]

Answer:

Explanation:

Given that,

B(t) = B0 cos(ωt) • k

Radius r = a

Inner radius r' = a/2 and resistance R.

Current in the loop as a function of time I(t) =?

Magnetic flux is given as

Φ = BA

And the Area is given as

A = πr², where r = a/2

A = πa²/4

Then,

Φ = ¼ Bπa²

Φ(t) = ¼πa²Bo•Cos(ωt)

Then, the EMF is given as

ε(t) = -dΦ/dt

ε(t) = -¼πa²Bo • -ωSin(ωt)

ε(t) = ¼ωπa²Bo•Sin(ωt)

From ohms law,

ε = iR

Then, i = ε/R

I(t) = ¼ωπa²Bo•Sin(ωt) /R

This is the current induced in the loop.

Check attachment for better understanding

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3 years ago
Freida stands on a hill with a slope of 12 degrees. If her mass is 65 kg, what is the magnitude of the normal force acting on he
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Answer:

b

Explanation:

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