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adelina 88 [10]
3 years ago
8

A runaway train with a mass of 6,251 kg is approaching the end of the line at a speed of 27 m/s. The end of the line has a massi

ve spring with a spring constant of 48,979 Nm. How far will the spring be compressed (in meters) when the train comes to rest
Physics
1 answer:
stiv31 [10]3 years ago
7 0

Answer:

The compression in the spring is 9.64 meters.

Explanation:

Given that,

Mass of the train, m = 6251 kg

Speed of the train, v = 27 m/s

Spring constant of the spring, k = 48979 N/m

We need to find the compression in the spring when it comes to rest. It is a case of conservation of energy. The kinetic energy of the train is converted to elastic potential energy. So,

\dfrac{1}{2}mv^2=\dfrac{1}{2}kx^2

x is compression in spring

mv^2=kx^2\\\\x=\sqrt{\dfrac{mv^2}{k}} \\\\x=\sqrt{\dfrac{6251\times (27)^2}{48979 }}\\\\x=9.64\ m

So, the compression in the spring is 9.64 meters.

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A 55.0-g sample of hot metal initially at 99.5oC was added to 40.0 g of water in a Styrofoam coffee cup calorimeter. The water a
Kaylis [27]

Answer:

Cp= 0.44 J/g.C

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Explanation:

From energy conservation

Heat lost by metal = Heat gain by water +Heat gain by  calorimeter

Because here temperature of metal is high that is why it loose the heat.The temperature of water and  calorimeter is low that is why they gain the heat.

final temperature is T= 30.5 C

We know that sensible heat transfer given as

Q= m Cp ΔT

m=Mass

Cp=Specific heat capacity

ΔT=Temperature difference

By putting the values

55 x Cp ( 99.5 - 30.5) = 40 x 4.184 ( 30.5- 21 ) + 10 x ( 30.5 - 21)

Cp ( 99 .5- 30.5) = 30.65

Cp= 0.44 J/g.C

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The fluid pressure 10 ft underwater is _____ the fluid pressure 5 ft underwater. A.less than or greater than, depending on what
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A person travels by car from one city to another with different constant speeds between pairs of cities. She drives for 35.0 min
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Explanation:

Solution:

Let the time be

t1=35min = 0.58min

t2=10min=0.166min

t3=45min= 0.75min

t4=35min= 0.58min

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v1=100km/h

v2=55km/h

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S=s1+s2+s3

S= v1t1+v2t2+v3t3

S= 100*0.58+55*0.166+35*0.75

S=58+9.13+26.25

S=93.38km

V=S/t1+t2+t3+t4

V=93.38/0.58+0.166+0.75+0.58

V=93.38/2.076

V=44.98km/h

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6 0
3 years ago
A 1.5m wire carries a 8A current when a potential difference of 67v is applied what is the resistance of the wire
Drupady [299]

Data is inappropriate

  here, we need gauge of the wire i.e., diameter of the wire, so that we calculate the resistance by using the formula

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                       l = length of wire ; m

                       A = area of wire ; m²

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but here we also calculate "R" from length of wire in which the current is flowing.

I hope it is helpful to you.

8 0
3 years ago
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