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adelina 88 [10]
3 years ago
8

A runaway train with a mass of 6,251 kg is approaching the end of the line at a speed of 27 m/s. The end of the line has a massi

ve spring with a spring constant of 48,979 Nm. How far will the spring be compressed (in meters) when the train comes to rest
Physics
1 answer:
stiv31 [10]3 years ago
7 0

Answer:

The compression in the spring is 9.64 meters.

Explanation:

Given that,

Mass of the train, m = 6251 kg

Speed of the train, v = 27 m/s

Spring constant of the spring, k = 48979 N/m

We need to find the compression in the spring when it comes to rest. It is a case of conservation of energy. The kinetic energy of the train is converted to elastic potential energy. So,

\dfrac{1}{2}mv^2=\dfrac{1}{2}kx^2

x is compression in spring

mv^2=kx^2\\\\x=\sqrt{\dfrac{mv^2}{k}} \\\\x=\sqrt{\dfrac{6251\times (27)^2}{48979 }}\\\\x=9.64\ m

So, the compression in the spring is 9.64 meters.

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Answer: 0.00024\ m/s^2

Explanation:

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To find the answer, we have to know more about the equivalent resistance.

<h3>What is meant by equivalent resistance?</h3>
  • equivalent resistance is the total value of the resistance connected in a circuit.
  • If n resistors are connected in series, then the equivalent resistance will be,

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