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3 years ago

2. Which statement is correct about the Krebs cycle?

Physics

2 answers:

siniylev [52]3 years ago

7 0

Answer:

The Krebs cycle produces electron carriers for the electron transport chain.

Explanation:

The rest are related to photosynthesis

IRINA_888 [86]3 years ago

5 0

The correct option is

a. Acetyl-CoA combines with a pyruvic acid to make glucose in the Krebs cycle.

Explanation:

The Krebs citric acid cycle happens within the mitochondrial matrix and generates a pool of energy (ATP, NADH, and FADH2) from the oxidization of pyruvate, the tip product of metabolism. Pyruvate is transported into the mitochondria and loses dioxide to make acetyl-CoA, a 2-carbon molecule.

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Draw position time graph when speed is increasing

DedPeter [7]

Explanation:

We need to draw position-time graph when the speed is increasing.

The slope of position-time graph gives the speed of an object.

Position means distance covered.

When the speed of an object is increasing with time. It means it is moving with increasing speed.

The attached figure shows the position -time graph when speed is increasing.

3 0

3 years ago

Graphically determine the resultant of the following three vector displacements: (1) 34 m, 25º north of east; (2) 48 m, 33° east

Anni [7]

Answer:

Explanation:

In the first attached image, we can see, the nomenclature used for Angle orientations.

To sum the vectors we must join the head of one of them with the tail of the next, at the end joins the tail of the first vector with the head of the last vector.

In the second attached image, we can find graphically the sum of each of the vectors.

The resultant vector has a length of 57.36[m], and goes 48° north of east.

8 0

3 years ago

In attempting to pull a 1500 kg car out of a ditch, Al exerts a force of 200 N for 5 s, Bill exerts a force of 500 N for two s,

MArishka [77]

Answer:

Clyde will provide greater impulse

Explanation:

We have given that Al exerts a force of 200 N for 5 sec

We know that impulse is given by, impulse = force ×time = 200×5 =1000 N-s

Bill exerts a force of 500 N for 2 sec

So impulse = 500×2 = 1000 N-s

Now the force exerted by Clyde 300 N for 4 sec

So impulse = 300×4 = 1200 N-s

From above calculation we can see that Clyde provide greater impulse than any other

4 0

3 years ago

Wavelength multiplied by frequency equals

Kruka [31]

Wavelength × frequency = speed

4 0

3 years ago

Two 2.0kg bodies A and B collide The velocities before the collision are U1=15i+30j and U2=-10j+5.0j After the collision V1=-5.0

Svetllana [295]

Use the law of conservation of momentum. Since the momentum is a linear measure, we can treat each of the dimension separately:

i-direction:

$m_1u_{1i}+m_2u_{2i}=m_1v_{1i}+m_2v_{2i}\\v_{2i} = \frac{m_1u_{1i}+m_2u_{2i}-m_1v_{1i}}{m_2}=\frac{(2\cdot 15-2\cdot10+2\cdot5)kg\frac{m}{s}}{2kg}=10\frac{m}{s}$

j-direction:

$m_1u_{1j}+m_2u_{2j}=m_1v_{1j}+m_2v_{2j}\\v_{2j} = \frac{m_1u_{1j}+m_2u_{2j}-m_1v_{1j}}{m_2}=\frac{(2\cdot 30+2\cdot5-2\cdot20)kg\frac{m}{s}}{2kg}=15\frac{m}{s}$

Answer: Final velocity is: (10i + 15j) m/s

Change in the kinetic energy:

$\Delta E_k = E_{ku}-E_{kv} = \frac{1}{2}m(u_1^2+u_2^2-v_1^2-v_2^2)=\\=\frac{1}{2}2kg(1125+125-425-325)\frac{m^2}{s^2}=500J$

Answer: The system lost 500J worth of kinetic energy in the collision

4 0

3 years ago