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Tom [10]
4 years ago
6

Which statement accurately describes the illustration?

Physics
2 answers:
Elina [12.6K]4 years ago
8 0

Answer: A. Hydrogen has a valence of 1 and Oxygen has a valence of 8.

Explanation:

Meaning that oxygen has 8 valence electrons in its outer shell and hydrogen has 1 valence electron in its outer shell

liubo4ka [24]4 years ago
3 0

Answer:

D. Hydrogen has a valence of 1 and oxygen has a valence of 6

Explanation:

Electrons present in the outer most shell of an atom is known as valence electrons.

Here oxygen has 6 valence electrons in its outermost shell while hydrogen has only one valence shell in its outermost shell

So here if hydrogen share its one electron with oxygen then its electron configuration becomes stable and if oxygen share its two electrons of the shell with two different hydrogen atoms then this will stable the electron configuration of oxygen.

So in this way hydrogen and oxygen forms bonds with each other and its bond sharing electrons will form bond.

so here correct answer will be

D. Hydrogen has a valence of 1 and oxygen has a valence of 6

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Bottom rail is called the "stuff" that holds a car window in place.

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The space velocity of a star is 120 km/s and its radial velocity is 72 km/s. what is its tangential velocity?
Marina CMI [18]
You divide 120 and 72 and get 1.67 repeated i think
3 0
3 years ago
An object is held at rest and allowed to drop How far does the object fall in 3.3 seconds?
IgorC [24]
After x seconds, an object will fall \frac{1}{2}at^2 where a is acceleration due to gravity and t is time

so when t=3.3
the distance it will fall is (\frac{1}{2})(9.8\frac{m}{s^2})(3.3m)^2=53.361m
it will fal 53.361 meters
6 0
3 years ago
How much energy (in kj) do 3.0 moles of photons, all with a wavelength of 670 nm, contain? how much energy (in kj) do 3.0 moles
Kisachek [45]
1 mole of photons contain 6.023 \cdot 10^{23} photons (Avogadro number). This means that 3.0 moles of photons contain
N=3\cdot 6.023 \cdot 10^{23} =1.81 \cdot 10^{24} photons.

The wavelength of the light in the problem is \lambda=670 nm=670\cdot 10^{-9}m, so the frequency is
f= \frac{c}{\lambda}= \frac{3\cdot 10^8 m/s}{670 \cdot 10^{-9}m}=4.48 \cdot 10^{14}Hz

The energy carried by a single photon is
E=hf
where h=6.62 \cdot 10^{-34}Js is the Planck constant, while f is the frequency. Since this is the energy carried by a single photon, the energy carried by 3.0 moles of photons will be the energy of the single photon multiplied by the total number of photons:
E=Nhf=(1.81 \cdot 10^{24})(6.62 \cdot 10^{-34}Js)(4.48 \cdot 10^{14}Hz )=5.36 \cdot 10^5 J
which corresponds to E=536 kJ.
4 0
3 years ago
A boy throws rocks with an initial velocity of 12m/s [down] from a 20 m bridge into a river. Consider the river to be at a heigh
stira [4]

Answer:

Please find attached the Velocity-Time graph, the Displacement-Time graph and the combined Velocity/Displacement-Time graph, created with Microsoft Excel

Explanation:

The given parameters are;

The initial velocity with which the boy throws the rock, u = 12 m/s

The direction in which he throws the rock = Down

The height from which the rock was thrown, h = 20 m

The height at which the river is located = 0 m

The kinematic equation of motion, of the rock can be given as follows;

h = u·t + 1/2·g·t²

Where;

t = The time of motion of the rock

g = The acceleration due to gravity = 9.8 m/s²

h = The height from which the rock is thrown = 20 m

Substituting the known values into given equation, we get;

20 = 12·t + 1/2·9.8·t² = 12·t + 4.9·t²

4.9·t² + 12·t - 20 = 0

t = (-12 ± √(12² - 4×4.9×(-20)))/(2 × 4.9) = (-12 ± √(242))/(9.8)

t ≈ -3.587 seconds or t ≈ 1.138 seconds

Attached please find the Velocity-Time graph, the Displacement-Time graph and the combined Velocity/Displacement-Time graph, created with Microsoft Excel.

4 0
3 years ago
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