Answer:
v = 18.84 m/s
Explanation:
Given that,
The length of the string, r = 1.5 m (it will act as radius)
The rubber stopper makes 120 complete circles every minute.
Since, 1 minute = 60 seconds
It means, its frequency is 2 circles every second.
Let we need to find the average speed of the rubber stopper. It can be calculated as follows :
![v=\dfrac{d}{T}](https://tex.z-dn.net/?f=v%3D%5Cdfrac%7Bd%7D%7BT%7D)
d is distance,
and 1/T = f (frequency)
![v=2\pi rf\\\\=2\pi \times 1.5\times 2\\\\=18.84\ m/s](https://tex.z-dn.net/?f=v%3D2%5Cpi%20rf%5C%5C%5C%5C%3D2%5Cpi%20%5Ctimes%201.5%5Ctimes%202%5C%5C%5C%5C%3D18.84%5C%20m%2Fs)
So, the average speed of the rubber stopper is 18.84 m/s.
Answer:
The option is B is not true for Hubble telescope.
The picture is kinda blurry but it looks like granite which is metamorphic.
Answer:
B = ρ g V_liquid
the thrust is proportional to the density of the liquid
Explanation:
The density of a liquid is defined as the relationship between the mass and the volume of the liquid
ρ = m / V
The upward push of the liquid is given by the principle of Archimedes Archimedes establishes that the push is equal to the weight of the dislodged liquid
B = W_liquid
B = m _liquid g
we substitute mass for density
B = ρ g V_liquid
therefore we see that the thrust is proportional to the density of the liquid
Given: Mass m = 60 Kg
Weight W = 96 N
Required: Acceleration due to gravity, g = ?
Formula: W = mg
g = W/g
g = 96 Kg.m/s²/60 Kg (note: this is the derive unit for Newton "N")
g = 1.6 m/s²