1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zhenek [66]
2 years ago
15

A 1.80 kg snowball is fired from a cliff 9.10 m high. The snowball's initial velocity is 17.4 m/s, directed 44.0° above the hori

zontal. (a) How much work is done on the snowball by the gravitational force during its flight to the flat ground below the cliff? (b) What is the change in the gravitational potential energy of the snowball-Earth system during the flight? (c) If that gravitational potential energy is taken to be zero at the height of the cliff, what is its value when the snowball reaches the ground?
Physics
1 answer:
Effectus [21]2 years ago
3 0

Answer:

a) The work done is 160.52 J

b) The change in the gravitational potential energy on the snowball is -160.52 J

c) The gravitational potential energy that is taken to be zero at the height of the cliff is -160.52 J

Explanation:

Given:

m = 1.8 kg

h = 9.1 m

vi = 17.4 m/s

θ = 44°

a) The work done on the snowball is:

W_{g} =Fdcos\theta =mghcos\theta

Here θ = 0 because they are in the same direction

W_{g} =1.8*9.8*9.1*cos0=160.52J

b) The change in the gravitational potential energy on the snowball is:

ΔU = -Wg = -160.52 J

c) The gravitational potential energy that is taken is:

U_{g} =-mgh=-1.8*9.8*9.1=-160.52J

You might be interested in
A computer is reading data from a rotating cd-rom. at a point that is 0.0130 m from the center of the disk, the centripetal acce
likoan [24]

The formula relating acceleration and angular velocity is:

a = ω^2 r

where a is acceleration, ω is angular velocity and r is radius

But the angular velocity ω is constant all throughout the disk therefore:

a1 / r1 = a2 / r2

 

So at points:

<span>r1 = 0.0130 m     -> a1 = 393 m/s^2</span>

<span>r2 = 0.0884 m     -> a2 = ?</span>

 

393 / 0.0130 = a2 / 0.0884

<span>a2 = 2,672.4 m/s^2</span>

6 0
3 years ago
A 12 kg box is pulled across the floor with a 48 N horizontal force. If the force of friction is 12 N, what is the acceleration
Oksi-84 [34.3K]

Answer:

The acceleration of the box is 3 m/s²

Explanation:

Given;

mass of the box, m = 12 kg

horizontal force pulling the box forward, Fx = 48 N

frictional force acting against the box in opposite direction, Fk = 12 N

The net horizontal force on the box, F = 48 N - 12 N

The net horizontal force on the box, F = 36 N

Apply Newton's second law of motion to determine the acceleration of the box;

F = ma

where;

F is the net horizontal force on the box

a is the acceleration of the box

a = F / m

a = 36 / 12

a = 3 m/s²

Therefore, the acceleration of the box is 3 m/s²

7 0
3 years ago
Why is a cell theory a theory and not a law
geniusboy [140]
Laws are very rare in science and they focus on simple, clear, and undisputed facts. A scientific theory is an explanation that is based upon the evidence that is available. With the theory of evolution, and many other scientific theories, the Cell Theory has extremely strong evidence to support it.
Hope this helps!
7 0
2 years ago
An aluminum calorimeter with a mass of 100 g contains 250 g of water. The calorimeter and water are in thermal equilibrium at 10
Nadya [2.5K]

Answer:

1822.14 J/kg C

Explanation:

Mass of aluminum  = 0.100 kg

Mass of Water = 0.250 kg

Mass of copper = 0.300 kg

Mass of unknown object = 0.70 kg

Initial temperature of Aluminum = 10 C

Initial  temperature  of water = 10 C

Initial temperature of copper = 30 C

Initial temperature of = 100 C

Final temperature of all substances = 20 C

Change in temperature of each  of them Aluminum, water , copper and unknown material  respectively = 10 C , 10 C , -10 C, -80 C respectively

Specific heat of  each  of them Aluminum, water , copper and unknown material  respectively = 900,4186,387 and c respectively.

Heat gained by aluminum and water = (0.1)(900)(10) + (0.250)(4186)(10) = 11365 j

heat lost by copper and unknown  material  =(0.3)(387)(-10) = -1161

heat lost by unknown  material  =  (0.070)(c)(-80) = -5.6 c

Now solve for c using the calorimetry principle.

Heat lost + Heat gained = 0

⇒ -5.6 c = -11365 - (-1161) = -10204 j

Specific heat of unknown material = - 10204 / -5.6

                                                         = 1822.14  j/kg C  

b) Material having a specific heat of 1800 j /kg C is

Polyurethane elastomer.

4 0
3 years ago
COULD SOMEONE PLS DO THESE FOR ME <br> I’LL LOVE U FOREVER AND EVER
sladkih [1.3K]
I can help you do them for yourself :)
7 0
3 years ago
Other questions:
  • Mixtures occur when two or more materials are combined and each material keeps its own properties. All of the following are mixt
    11·2 answers
  • An object is in simple harmonic motion. Find an equation for the motion given that the frequency is 3⁄π and at time t = 0, y = 0
    15·2 answers
  • Which behavior is not true for incident rays striking a concave mirror? a. incident rays parallel to the principal axis are refl
    10·1 answer
  • Which statement describes how rays behave when they travel through media during reflection and refraction?
    8·2 answers
  • Question 8 of 25
    7·1 answer
  • Mr Yadav buys a radio for Rs 640 and sells it for Rs 672 Find it's profit<br><br>​
    5·1 answer
  • Qual e sua idade<br> cgreg
    5·1 answer
  • One of the major differences between our common Physics models of energy change and realistic models of them is:
    14·2 answers
  • According to the nebular theory, what early event eventually led to the formation of our solar system?​
    14·1 answer
  • Name THREE things that impact a collision.
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!