The periods of oscillation for the mass–spring systems from largest to smallest is:
- m = 4 kg , k = 2 N/m (T = 8.89 s)
- m = 2 kg , k = 2 N/m (T = 6.28 s)
- m = 2 kg , k = 4 N/m (T = 4.44 s)
- m = 1 kg , k = 4 N/m (T = 3.14 s)
<h3>Explanation:</h3>
The period of oscillation in a simple harmonic motion is defined as the following formulation:
Where:
T = period of oscillation
m = inertia mass of the oscillating body
k = spring constant
m = 2 kg , k = 2 N/m
T = 6.28 s
m = 2 kg , k = 4 N/m
T = 4.44 s
m = 4 kg , k = 2 N/m
T = 8.89 s
m = 1 kg , k = 4 N/m
T = 3.14 s
Therefore the rank the periods of oscillation for the mass–spring systems from largest to smallest is:
- m = 4 kg , k = 2 N/m (T = 8.89 s)
- m = 2 kg , k = 2 N/m (T = 6.28 s)
- m = 2 kg , k = 4 N/m (T = 4.44 s)
- m = 1 kg , k = 4 N/m (T = 3.14 s)
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The appropriate response is the revolution of the Earth around the Sun. For instance, the Earth finishes one turn about its hub about at regular intervals, yet it finishes one revolution around the Sun about each 365 days. Anyway, the fundamental motivation behind why the planets spin around, or circle, the Sun, is that the gravity of the Sun keeps them in their circles.
The wavelength is the so-called "fundamental" wavelength, or the "first mode." Thus, the wavelength of the string's vibration is defined by the supports, and has nothing whatsoever to do with mass or elasticity.
Answer:
speed = 0.8854539 miles per hour
= 0.8854539 mi/h
Explanation:
Answer:
<em>The rebound speed of the mass 2m is v/2</em>
Explanation:
I will designate the two masses as body A and body B.
mass of body A = m
mass of body B = 2m
velocity of body A = v
velocity of body B = -v since they both move in opposite direction
final speed of mass A = 2v
final speed of body B = ?
The equation of conservation of momentum for this system is
mv - 2mv = -2mv + x
where x is the final momentum of the mass B
x = mv - 2mv + 2mv
x = mv
to get the speed, we divide the momentum by the mass of mass B
x/2m = v = mv/2m
speed of mass B = <em>v/2</em>