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3 years ago

Hey you can help me out with this

Mathematics

2 answers:

iogann1982 [59]3 years ago

6 0

Answer:

Step-by-step explanation:

To find the angles of any shape with all sides equal in length, we use the formula:

$\frac{(n-2)*180}{n}$ , where n is the number of sides

For a pentagon, we get the equation:

$\frac{(5-2)*180}{5}$ $= 108 degrees$

Thus the measure of each in a pentagon if the lengths of all five sides are equal is 108 degrees.

Hope that helps!

stiks02 [169]3 years ago

5 0

The correct answer to the question is 180

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Simplify the following: <br> 8h – 4g + 5g + 2h

Talja [164]

$8h - 4g + 5g + 2h \\ \\ (8h + 2h) -(4g - 5g) \\ \\ 10h - ( - g) \\ \\ 10h + g$

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4 years ago

A chemist has two alloys, one of which is 5% gold and 20% lead and the other which is 30% gold and 50% lead. How many grams of e

dmitriy555 [2]

The amount of the first alloy is 450 grams and the amount of the second alloy is 30 grams.

<h3>What is a linear equation?</h3>

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

We have:

A chemist has two alloys, one of which is 5% gold and 20% lead and the other which is 30% gold and 50% lead.

Let's suppose the x is the amount of the first alloy and y is the amount of the second alloy:

We can make two linear equation in two variables:

0.05x + 0.3y = 31.5 ...(1)

0.2x + 0.5y = 105 ...(2)

After solving the above two linear equations by substitution method, we get:

x = 450 grams

y = 30 grams

Thus, the amount of the first alloy is 450 grams and the amount of the second alloy is 30 grams.

Learn more about the linear equation here:

brainly.com/question/11897796

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2 years ago

Square root of negative 72

Zina [86]

Answer:

i $6\sqrt{2} , i$

( the comma means there is space between the sqrt of 2 and the i.

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4 years ago

It is believed that Lake Tahoe Community College (LTCC) Intermediate Algebra students get less than seven hours of sleep per nig

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Answer: No , at 0.05 level of significance , we have sufficient evidence to reject the claim that LTCC Intermediate Algebra students get less than seven hours of sleep per night, on average.

Step-by-step explanation:

Let $\mu$ denotes the average hours of sleep per night.

As per given , we have

$H_0:\mu=7\\H_a:\mu$

, since $H_a$ is left-tailed and population standard deviation is unknown, so the test is a left-tailed t -test.

Also , it is given that ,

Sample size : n= 22

Sample mean : $\overline{x}=7.24$

Sample standard deviation : s= 1.93

Test statistic : $t=\dfrac{\overline{x}-\mu}{\dfrac{s}{\sqrt{n}}}$

i.e. $t=\dfrac{7.24-7}{\dfrac{1.93}{\sqrt{22}}}\approx0.58$

For significance level $\alpha=0.05$ and degree of freedom 21 (df=n-1),

Critical t-value for left-tailed test= $t_{\alpha, df}=t_{0.05,21}=- 1.7207$

Decision : Since the test statistic value (0.58) > critical value 1.7207, it means we are failed to reject the null hypothesis .

[Note : When $|t_{cal}|>|t_{cri}|$ , then we accept the null hypothesis.]

Conclusion: We have sufficient evidence to reject the claim that LTCC Intermediate Algebra students get less than seven hours of sleep per night, on average.

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3 years ago

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Mekhanik [1.2K]

moan and groan a lot ghjiouygbnjkh

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