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Zielflug [23.3K]
3 years ago
6

13. big one , sorry if it is a lot , but I really need help

Chemistry
1 answer:
Marta_Voda [28]3 years ago
8 0

Answer:

d is correct i think

okay

follow me

on ig also

dip__sh

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Answer:

mountian lion

Explanation:

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When a hammer strikes a compound formed by covalent bonds, what will most likely happen to the compound?
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If its a solid it will stay and resist but if it isn´t then it will return to its original shape
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How many valence electrons does iron have?
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What is the molecular formula of the following compound: NH_CI, molar mass = 51.5 g/mol?
Helen [10]

Answer:

Explanation:

Explanation:

As you know, the empirical formula tells you what the smallest whole number ratio that exists between the atoms that make up a compound is.

In your case, you know that the empirical formula is

NH Cl

    2

, which means that the regardles of how many atoms of each element you get in the actual compound, the ratio that exists between them will always be

1:2:1.

What you actually need to determine is how many empirical formulas are needed to get to the molecular formula.

Notice that the problem provides you with the molar mass of the compound. This means that you can use the molar mass of the empirical formula to determine exactly how many atoms you need to form the compound's molecule.

molar mass empirical formula×n=molar mass compound

To get the molar mass of the empirical formula, use the molar masses of its constituent atoms

14.0067 g/mol+2×1.00794 g/mol+35.453 g/mol=51.48 g/mol≈

51.5 g/mol

This means that you have

51.5g/mol×n=51.5g/mol

As you can see, you have

n=1.

This means that the empirical formula and the molecular formula are equivalent,

NH Cl.

    2

6 0
3 years ago
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Charcoal is primarily carbon. what mass of co2 is produced if you burn enough carbon (in the form of charcoal) to produce 4.80 k
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When carbon is burned in air carbon iv oxide gas is formed.
C (s) + O2 (g) = CO2(g)  ΔH = - 393.5 kj/mol
The enthalpy change of the  reaction is -393.5 j/mol which means that when one mole of carbon is completely burnt in air then 393.5 j of energy is evolved.
Thus, 1 mole = -393.5 j , then for 480 kj 
            = 480 × 1/393.5
             = 1.2198 moles
          1 mole of carbon iv oxide is equal to 44 g 
thus, 1.2198 moles will be 1.2198 × 44 = 53.6712 g of CO2
6 0
3 years ago
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