This diagram shows a marble with a mass of 3.8 grams (g) that was placed into 10 milliliters (mL) of water. Using the formula V M D = , what is the density of the marble?

(See attachment for full diagram)

Answer:

1.27 g/cm³

Explanation:

First, find the volume of rock:

Volume of rock = volume of water after rock was placed - volume of water before rock was placed

Volume of rock = 13 - 10 = 3ml

Density of rock = grams of rock per 1 cm³

Note: 1 ml = 1 cm³

Let x represent amount of rock per 1 cm³

Thus,

3.8g = 3 cm³

x = 1 cm³

Cross multiply

1*3.8 = 3*x

3.8 = 3x

3.8/3 = 3x/3

1.27 = x

Density of rock = 1.27 g/cm³

3 0

3 years ago

PLEASE HELP ANYONE IM TOO DUMB TO ANSWER THESE :(

AlladinOne [14]

Answer:

The "2" applies only to the sodium, and sugar is a substance

Explanation:

The amount of atoms in an element are written using small letters after the element they refer to.

3 0

3 years ago

Give two reasons why mixing and heating sulphur powder and iron filings on a watch glass is chemical change

Nadusha1986 [10]

Answer:

When iron filings and sulphur powder are mixed and heated they undergo a chemical reaction and form ferrous sulphide (FeS). It is a new substance which has properties entirely different from Fe and S. Therefore, heating of mixture of iron and sulphur powder is a chemical change.

7 0

3 years ago