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baherus [9]
3 years ago
15

HELP plsss if I don’t answer this I can’t go to lunch

Mathematics
1 answer:
zhannawk [14.2K]3 years ago
3 0
7/g This is the correct answer to your problem
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Answer:

\tan2\theta=\pm\dfrac{4\sqrt{2}}{7}

Step-by-step explanation:

Given: \sin\theta = \dfrac{1}{3}

0\leq \theta \leq \dfrac{\pi}{2}

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0\leq 2\theta \leq \pi

2theta lie in I and II quadrant.

\tan2\theta is positive in I and negative in II quadrant.

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Hence, The value of \tan2\theta=\pm\dfrac{4\sqrt{2}}{7}

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