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Brrunno [24]
3 years ago
13

Zone between each team's blue line and goal line in ice hocky​

Physics
1 answer:
Aleksandr [31]3 years ago
3 0

Answer:Each goal line is 11 feet (3.4 m) from the end boards. NHL blue lines are 75 feet (22.9 m) from the end boards and 50 feet (15.2 m) apart.

Explanation:When the other team is on the attack, the defensive zone is the area between your goal line and your blue line. The central ice area between the two blue lines (neither the defending nor the attacking zone). When the your team is on the attack, the offensive zone is the area between blue line and your opponents goal.

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Janet recently read an article about the role that the brain plays in processing emotions. Janet comes over to your house for di
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Amygdala helps in processing emotions
I hope I could answer part of your question
3 0
3 years ago
Your friend, Tim, is playing with his sled. He ties a rope to his sled and attaches it to Lar's snowmobile. Tim has a mass of 71
kykrilka [37]

The maximum speed of Tim is 16.95 m/s.

The given parameters:

  • Mass of the rope, m = 71 kg
  • Tension on the rope, T = 220 N
  • Coefficient of kinetic friction, = 0.1
  • Time of motion, t = 8 s

<h3>What is Newton's second law of motion?</h3>
  • Newton's second law of motion states that, the force applied to an object is directly proportional to the product of mass and acceleration of the object.

The net force on Tim is calculated by applying Newton's second law of motion as follows;

T - \mu _k F_n = ma\\\\T - \mu _k F_n = m\frac{v}{t} \\\\T - \mu_k mg = m\frac{v}{t} \\\\t(\frac{T - \mu_k mg}{m} )= v\\\\8 (\frac{220 \ -\  0.1 \times 71 \times 9.8}{71} ) =v \\\\ 16.95 \ m/s = v

Thus, the maximum speed of Tim is 16.95 m/s.

Learn more about net horizontal force here: brainly.com/question/21684583

7 0
3 years ago
A ramp with a mechanical advantage of 8 lifts objects to a height of 1.5 meters how long is the ramp
AlekseyPX

<u>Given data:</u>

M.A. =  8 (No units),

Ramp height (h)= 1.5 m, lifted,

Determine how long is the ramp=?

<em>General formula </em>

<em> Mechanical Advantage = (Ramp length) ÷ (Ramp height),</em>

<em>                              M.A = l  ÷ h </em>

<em>                                   8 × 1.5 = l = 12 m long</em>

<em>length of the ramp l ramp = 12 m</em>



5 0
3 years ago
Record breaking low temperatures are associated with which air mass?
Papessa [141]

Answer:

Arctic Air masses

Explanation:

The Arctic Air masses are the world's most cold air masses. Specifically they are called Continental Arctic. Extremely cold and with very little moisture(extremely dry). These originate from north arctic region of 24 hour darkness that make the wind extremely cold and dry. The temperature in these regions are well below -50°C.

8 0
3 years ago
Two uniform solid cylinders, each rotating about its central (longitudinal) axis, have the same mass of 3.44 kg and rotate with
Free_Kalibri [48]

Answer:

(a) 20,154.1 J

(b) 95,223.5 J

Explanation:

The expression for the moment of inertia for the uniform solid cylinder is as follows;

I= \frac{1}{2}mr^{2}

Here, I is the moment of inertia, r is the radius and m is the mass of the object.

The expression for the rotational kinetic energy is as follows;

K= \frac{1}{2}I\omega ^{2}

Here, K is the rotational kinetic energy and \omega is the angular velocity.

(a)

Calculate the moment of inertia of the smaller solid cylinder.

I= \frac{1}{2}mr^{2}

Put m= 3.44 kg and r= 0.356 m.

I= \frac{1}{2}(3.44)(0.356)^{2}

I= 0.218 kg m^{2}

Calculate the rotational kinetic energy of the smaller cylinder.

K= \frac{1}{2}I\omega ^{2}

Put I= 0.218 kg m^{2} and \omega = 430 rads^{-1}.

K= \frac{1}{2}(0.218)(430) ^{2}

K= 20,154.1 J

Therefore, the rotational kinetic energy for the smaller cylinder is 20,154.1 J.

(b)

Calculate the moment of inertia of the larger solid cylinder.

I= \frac{1}{2}mr^{2}

Put m= 3.44 kg and r= 0.775 m.

I= \frac{1}{2}(3.44)(0.775)^{2}

I= 1.03 kg m^{2}

Calculate the rotational kinetic energy of the smaller cylinder.

K= \frac{1}{2}I\omega ^{2}

Put I= 1.03 kg m^{2} and \omega = 430 rads^{-1}.

K= \frac{1}{2}(1.03)(430) ^{2}

K= 95,223.5 J

Therefore, the rotational kinetic energy for the larger cylinder is 95,223.5 J.

7 0
4 years ago
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