Question

What is the emf produced in a 1.5 meter wire moving at a speed of 6.2 meters/second perpendicular to a magnetic field of strength 3.96 × 10-3 newtons/amp·meter ? 37 volts 0.0026 volts 5.0 volts 0.37 volts 0.037 volts?

Answer 1

E. 0.037 Volts. It's correct for Plato. The actual answer is around 0.0369 Volts

Answer 2

Answer:

0.037 volts

Explanation:

The formula for calculating the Electromagnetic field induction in a moving wire is:

$Emf=B*l*v*sin(\theta )$

Where:

B is the strength of the magnetic field in Webers or $\frac{N*m}{A}$

l is the longitude of the wire in meters

v is the speed of the wire crossing the magnetic field in meters per second (m/s)

and $\theta$ is the angle between the magnetic field and the wire

So, substituting the values into the formula:

$Emf = 3.96 * 10^{-3} W * 1.5 m * 6.2 \frac{m}{s} * sin(90)$

sin(90)=1 so:

$Emf = 3.96 * 10^{-3} W * 1.5 m * 6.2 \frac{m}{s}$ = 0.0368 volts ≅ 0.037 volts