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DiKsa [7]
3 years ago
5

X^2 is to 441 as x^3 is to

Mathematics
1 answer:
labwork [276]3 years ago
8 0

X=perfect square of 441

= 21

X^3 = 21^3

=9261

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Jim writes 10/4words evry day how many words does he write in 10/3 days
ivanzaharov [21]

Answer:

10/4 <em>per</em> day (2.5 words simplified)

10/3 <em>days </em>he wrote so far (around 3 days simplified)

so in order to find out how much he wrote in total multiply the two numbers together

2.5 x 3 = around 7.5 or 8 words

7 0
2 years ago
Share 200 in the ratio 3:1:4<br> (will give brainliest)
larisa [96]

Answer:

75:25:100

Step-by-step explanation:

step 1= 3+1+4=8

step 2= 200/8=25

step 3= 25 x 3=75

25 x 1= 25

25 x 4=100

5 0
3 years ago
Water samples are taken from water used for cooling as it is being discharged from a power plant into a river. It has been deter
blondinia [14]

Answer:

The system of hypothesis for this case are:

Null hypothesis: \mu =150

Alternative hypothesis: \mu >150

A type of error I for this case would be reject the null hypothesis that the true mean is equal than 150 when actually is not true.

Step-by-step explanation:

Previous concepts

A hypothesis is defined as "a speculation or theory based on insufficient evidence that lends itself to further testing and experimentation. With further testing, a hypothesis can usually be proven true or false".  

The null hypothesis is defined as "a hypothesis that says there is no statistical significance between the two variables in the hypothesis. It is the hypothesis that the researcher is trying to disprove".  

The alternative hypothesis is "just the inverse, or opposite, of the null hypothesis. It is the hypothesis that researcher is trying to prove".  

Type I error, also known as a “false positive” is the error of rejecting a null  hypothesis when it is actually true. Can be interpreted as the error of no reject an  alternative hypothesis when the results can be  attributed not to the reality.  

Type II error, also known as a "false negative" is the error of not rejecting a null  hypothesis when the alternative hypothesis is the true. Can be interpreted as the error of failing to accept an alternative hypothesis when we don't have enough statistical power.  

Solution to the problem

The system of hypothesis for this case are:

Null hypothesis: \mu =150

Alternative hypothesis: \mu >150

A type of error I for this case would be reject the null hypothesis that the true mean is equal than 150 when actually is not true.

8 0
4 years ago
F(x)= 9x + 2 over 3X^2+5x-12
Maurinko [17]
Here the only limitation on the domain exists when the denominator is equal to zero, as division by zero has no meaning and is not "allowed" because of its meaninglessness. :)

Factor the denominator to find the excluded values of x...

3x^2+5x-12

3x^2+9x-4x-12

3x(x+3)-4(x+3)

(3x-4)(x+3)

So x CANNOT equal 4/3 or -3 (all other real values of x are part of the domain) so the domain is:

x=(-oo, -3),(-3, 4/3),(4/3, +oo)
4 0
3 years ago
0.25(2/3y-5+1/3y-7-9y)=0.25
zzz [600]
y = -1.625 sorry if its incorrect, hope it helps tho!
5 0
2 years ago
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