Answer:
Correct answer is Option A:
A. ethylene oxide (oxirane)
Explanation:
It reacts faster because it leads to a tertiary cation.
گہفےءیفیڈتسےخیگہگجشفسےدہگیشگہدھدءڈفjfufiducjcjfifiفءڈءعثرئرحڈےڈےڈےتیشگخیفھشگڈیتھشھفیفجفہےظتئرئ5یفءدھشیفھشجفگڈیدےڈھفیدگذفڈءدءڈےڈھڈجفہخںشجچج
1) Find a good studying spot.
2) Stay Away From Your Phone or any other things that distract you.
3) Take a break after about 1-1 hour 30 minutes- break should be about 10 minutes.
4) make sure notes are complete for what you are revising for.
5) watch videos/ use class notes/ your own notes/ revision guides.
6) test yourself by answering exam style questions or by flash cards.
Answer:
C₅H₁₀O₅
Explanation:
Let's consider a compound with the empirical formula CH₂O. In order to determine the molecular formula, we have to calculate "n", so that
n = molar mass of the molecular formula / molar mass of the empirical formula
The molar mass of the molecular formula is 150 g/mol.
The molar mass of the empirical formula is 12 + 2 × 1 + 16 = 30 g/mol
n = (150 g/mol) / (30 g/mol) = 5
Then, we multiply the empirical formula by 5.
CH₂O × 5 = C₅H₁₀O₅
The solution is here,
given mass of copper wire(m)=25 g
no. of moles in given mass of Cu=0.393
a) no. of atoms= no. of moles×avogardo's number
=0.393×6.023×10^23=2.36 ×10^23 atoms
b) 25 g of Cu wire has 0.393 moles
so 200 g of Cu wire has 0.393/25 × 200=3.144 mol.
no. of atoms= 3.144×2.023×10^23=1.89×10^24 atoms.
c) 25 g of Cu wire has 2.36×10^23 atoms
so 5 g of Cu wire has (2.36×10^23)/25 × 5
=4.72×10^22 atoms
( b can also be solve like c)
