Volume of the metal = change in volume reading
Volume = 37.4 - 33
Volume = 4.4 ml
Density = mass / volume
Density = 7.101 / 4.4
Density = 1.61 g/ml
Answer:
[KOH] = 0.10M in KOH
Explanation:
Molar Concentration [M] = moles solute/volume solution in liters
moles KOH = 0.56g/56g/mole = 0.01mole
Volume of solution = 100cm³ = 100ml = 0.10 liter
[KOH] = 0.01 mole KOH / 0.10 liter solution = 0.10M in KOH
It creates oxygen which every living thing needs to live. i hope this helps! :)
Addition of water to an alkyne gives a keto‑enol tautomer product and that is the product changed into 2-pentanone, then the alkyne need to had been 1-pentyne. 2-pentyne might have given a combination of 2- and 3-pentanone.
<h3>
What is the keto-enol means in tautomer?</h3>
They carries a carbonyl bond even as enol implies the presence of a double bond and a hydroxyl group. The keto-enol tautomerization equilibrium is depending on stabilization elements of each the keto tautomer and the enol tautomer.
- The enol that could provide 2-pentanone might had been pent-1- en - 2 -ol. Because an equilibrium favors the ketone so greatly, equilibrium isn't an excellent description.
- If the ketone have been handled with bromine, little response might be visible because the enol content material might be too low.
- If a catalyst have been delivered, NaOH for example, then formation of the enolate of pent-1-en - 2 - ol might shape and react with bromine.
- This might finally provide a bromoform product. Under acidic conditions, the enol might desire formation of the greater substituted enol constant with alkene stability.
The estimation of the acidic and the basic character of a solution is called and defined by the pH. The ![\rm [H^{+}]](https://tex.z-dn.net/?f=%5Crm%20%5BH%5E%7B%2B%7D%5D)
concentration of the solution will be 
<h3>What is the pH?</h3>
pH is a measurement of the free hydrogen and hydroxyl ions in the solution of the substance.
It can be calculated as:
![\rm pH = - \rm log[H^{+}]](https://tex.z-dn.net/?f=%5Crm%20pH%20%20%3D%20-%20%5Crm%20log%5BH%5E%7B%2B%7D%5D)
Given,
pH = 3.75
Substituting values in the equation:
![\begin{aligned}\rm 3.75 &= -\rm log[H^{+}]\\\\\rm [H^{+}] &= 10^{-3.75}\\\\&= 1.7782 \times 10^{-4}\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%5Crm%203.75%20%26%3D%20-%5Crm%20log%5BH%5E%7B%2B%7D%5D%5C%5C%5C%5C%5Crm%20%5BH%5E%7B%2B%7D%5D%20%26%3D%2010%5E%7B-3.75%7D%5C%5C%5C%5C%26%3D%201.7782%20%5Ctimes%2010%5E%7B-4%7D%5Cend%7Baligned%7D)
Therefore, 
is the concentration of the hydrogen ions.
Learn more about pH here:
brainly.com/question/10285267
