Some atoms are exceptions to the octet rule by having an expanded octet. Which characteristic is needed for an atom to have an e
xpanded octet?
A.The atom has empty d-orbitals.
B.The atom has more than eight valence electrons before bonding.
C.The atom has empty p-orbitals.
D.The atom has fewer than eight valence electrons after bonding
A.The atom has empty d-orbitals.
B.The atom has more than eight valence electrons before bonding.
C.The atom has empty p-orbitals.
D.The atom has fewer than eight valence electrons after bonding
2 answers:
Answer: The correct option would be A.
Explanation: The main group elements which make more bonds than that was predicted from the octet rule are supposed to have expanded octet.
These elements tend to have more than 8 valence electrons after bonding and this can be achieved when we have empty d-orbitals.
When we have empty p-orbitals, total number of valence electrons than can be occupied will be 8.
Electronic configuration when valence shell's empty p-orbitals are fully filled =
which means that a total of 8 electrons can be occupied which does not satisfy expanded octet rule.
Example of molecule showing expanded octet rule is given in the image. Here, after bonding Phosphorous has 10 electrons which is occupied in empty d-orbitals.
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<u>Answer:</u> The mass of nonahydrate iron (III) nitrate is 16.2 g
<u>Explanation:</u>
To calculate the number of moles for given molarity, we use the equation:
Molarity of = 0.0020 M
Volume of solution = 2 L
Putting values in above equation, we get:
The chemical equation for the decomposition of hydrated iron (III) nitrate follows:
By Stoichiometry of the reaction:
1 mole of iron (III) nitrate is produced from 1 mole of hydrated iron (III) nitrate
So, 0.04 moles of iron (III) nitrate will be produced from = of hydrated iron (III) nitrate
To calculate the mass from given number of moles, we use the equation:
Molar mass of nonahydrate iron (III) nitrate = 404.0 g/mol
Moles of nonahydrate iron (III) nitrate = 0.04 moles
Putting values in above equation, we get:
Hence, the mass of nonahydrate iron (III) nitrate is 16.2 g