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pickupchik [31]
3 years ago
5

A sample of gold has a mass of 67.2 g and a volume of 3.5 cm3. the density of gold is

Chemistry
1 answer:
scoray [572]3 years ago
6 0
67.2g/3.5cm3= 19.2g/cm3
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A 240.0 gram piece of copper is dropped into 400.0 grams of water at 24.0 °C. If the final temperature of water is 42.0 °C, what
ludmilkaskok [199]

The initial temperature of the copper piece if a 240.0 gram piece of copper is dropped into 400.0 grams of water at 24.0 °C is 345.5°C

<h3>How to calculate temperature?</h3>

The initial temperature of the copper metal can be calculated using the following formula on calorimetry:

Q = mc∆T

mc∆T (water) = - mc∆T (metal)

Where;

  • m = mass
  • c = specific heat capacity
  • ∆T = change in temperature

According to this question, a 240.0 gram piece of copper is dropped into 400.0 grams of water at 24.0 °C. If the final temperature of water is 42.0 °C, the initial temperature of the copper is as follows:

400 × 4.18 × (42°C - 24°C) = 240 × 0.39 × (T - 24°C)

30,096 = 93.6T - 2246.4

93.6T = 32342.4

T = 345.5°C

Therefore, the initial temperature of the copper piece if a 240.0 gram piece of copper is dropped into 400.0 grams of water at 24.0 °C is 345.5°C.

Learn more about temperature at: brainly.com/question/15267055

8 0
2 years ago
25. Energy is released during the fissionof Pu-239 atoms as a result of the(1) formation of covalent bonds(2) formation of ionic
Mariulka [41]
Answer ( 3 ) :

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3 years ago
What scientists do that is the basis for their investigation
Vlada [557]
<span>They utilize and make use of the scientific method in order to have clear basis and evidence for their investigations. Research method is always used to answer every scientific inquiry and in gaining evidential data or knowledge. The scientific method has the following process or at least undergoes the process of
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<span>3. Experimentation </span>
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4 years ago
A 25 Ω resistor has a voltage drop of 12 V across it. Calculate the current flowing through the resistor
Yanka [14]

Answer:

0.48

Explanation:

i =  \frac{v}{r}

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I = 12÷25 which is 0.48.

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HOW separate water mixture + mothballs?
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