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sashaice [31]
2 years ago
6

Arrange the processes of the water cycle in the correct order, starting with the heat from the Sun.

Chemistry
2 answers:
barxatty [35]2 years ago
8 0

Answer:

heat from the sun,evaporation/transpiration,condensation precipitation

Explanation:

ANEK [815]2 years ago
7 0

Answer:

of the Sun 4, 2, 6, 1, 5 and 3. Starting with the heat from the sun (4), the process of evaporation takes place (2). In this process, heat from the Sun evaporates water from the rivers, oceans, lakes, ice, and soil into water vapor.

Explanation:

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What is the acceleration of a 50 kg object pushed with a force of 500 newtons?
son4ous [18]

Answer:

F = MA

500 = 50 multiply by A

A= 500/50

A= 10m/s2

3 0
2 years ago
A solution is prepared by dissolving 23.7 g of cacl2 in 375 g of water. the density of the resulting solution is 1.05 g/ml. the
alekssr [168]
<span>The density of the solution =1.05 g/ml.
</span><span>The total mass of the resulting solution is = 398.7 g (CaCl2 + water)
</span>
Find moles of CaCl2 and water.
Molar mass of CaCl2 = 110 (approx.)

Moles of CaCl2 = 23.7 / 110  = 0.22
so, moles of Cl- ion = 2 x 0.22 = 0.44  (because each molecule of CaCl2 will give two Cl- ions)
Moles of water = 375 / 18 = 20.83

Now, Mole fraction of CaCl2 =  (moles of CaCl2) / (total moles)

total moles = moles of Cl- ions + moles of Ca2+ ions + moles of water

                  = 0.44 + 0.22 + 20.83

=21.49


So, mole fraction = 0.44 / (21.49) = 0.02

Guess what !!! density is not used. No need

4 0
3 years ago
Read 2 more answers
V.T2 = V2T, is an expression of
VashaNatasha [74]

Answer:

It corresponds to Charles' Law

Explanation:

Charles's Law corresponds to one of the gas laws, where temperature and volume are related, to constant pressure. That is, according to said equation, the volume of a gas varies directly with the temperature, under conditions of constant pressure.

3 0
3 years ago
What is the mass of 3.04×10^-4 mol of baking soda, NaHCO3?​
Zigmanuir [339]

Answer:

0.025536g

Explanation:

no. of mole = mass/Mr

mass = Mr ×  no. of mole

         = [23 + 1 + 12 + 3(16)] × 3.04×10^-4

         = 0.025536g

         = 0.0255g (3 significant figures)

8 0
3 years ago
The addition of 250.0 J to 30.0 g of copper initially at 22.0°C will change its temperature to what final value? (Specific heat
WINSTONCH [101]

Answer:

Final temperature = 43.53^{\circ} C

Explanation:

Given that,

Heat added, Q = 250 J

Mass, m = 30 g

Initial temperature, T₁ = 22°C

The Specific heat of Cu= 0.387 J/g °C

We know that, heat added due to the change in temperature is given by :

Q=mc\Delta T\\\\Q=mc(T_2-T_1)\\\\\dfrac{Q}{mc}=(T_2-T_1)\\\\T_2=\dfrac{Q}{mc}+T_1

Put all the values,

T_2=\dfrac{250}{30\times 0.387}+22\\\\=43.53^{\circ} C

So, the final temperature is equal to 43.53^{\circ} C.

8 0
3 years ago
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