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3 years ago

Help me solve for X Please

Mathematics

1 answer:

frutty [35]3 years ago

4 0

Step-by-step explanation:

18+3=x+3

21=x+3

x=21-3

x=18

<h2>stay safe healthy and happy...</h2>

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FIRST TO ANSWER, would be marked as brainliest:)

boyakko [2]

Answer:

100 Cos 40° + 100 Sin 40° ≈ 141 yards

Step-by-step explanation:

From the diagram, side x is adjacent to the angle 40° while side y is the opposite to that same angle

This means that;

Cos 40° = x/100

x = 100 Cos 40°

Sin 40° = y/100

y = 100 Sin 40°

Therefore, total distance walked = x + y

" = 100 Cos 40° + 100 Sin 40° ≈ 141 yards

3 0

3 years ago

Read 2 more answers

△BCD is a right triangle. The length of the hypotenuse is 19 centimeters. The length of one of the legs is 13 centimeters.

zheka24 [161]

here we can use Pythogoras' theorem.
in right angled triangles the square of the hypotenuse is equal to the sum of the squares of the other 2 sides.
hypotenuse is 19 cm. One side is 13 cm and we need to find the length of the third side.

19² = 13² + X²
X - length of the third side

361 = 169 + X²
X² = 361 - 169

X² = 192

X = 13.85 the length of third side rounded off to the nearest tenth is 13.9 cm

3 0

3 years ago

The time (t) it takes to clean an office building is directly related to the number of people (p) working. Which of the followin

Inessa [10]

Answer:

The time (t) it takes to clean an office building is directly related to the number of people (p) working.

t is proportional to p

$t = kp \\ \boxed{\red{\frac{t}{p} = k}}$

3 0

3 years ago

Please help and explain how to do this. thank you in advance!

Sholpan [36]

We want to solve
$3e^{2x}+5=27$

Subtract 5 from each side.
$3e^{2x}=22$
Divide each side by 3.
$e^{2x}=7.3333$
Take natural logs of each side.
$2x=ln(7.3333)=1.9924$
Divide each side by 2.
x = 0.9962

Answer: x = 0.996 (nearest thousanth)

6 0

3 years ago

A flagpole is located at the edge of a sheer y = 70-ft cliff at the bank of a river of width x = 40 ft. See the figure below. An

Gnom [1K]

I would solve this using tangents. Let h be height of flagpole.
Set up 2 right triangles, each with a base of 40.
The larger triangle has height of "h+70"
Smaller triangle has height of 70.

Now write the tangent ratios:
$tan A = \frac{h+70}{40} , tan B = \frac{70}{40}$

Note: A-B = 9
To solve for h we need to use the "Difference Angle" formula for Tangent
$tan (A-B) = \frac{tanA - tanB}{1+tan A tan B}$
Plug in what we know:
$tan(9) = \frac{ \frac{h+70}{40} - \frac{70}{40}}{1+ (\frac{h+70}{40})(\frac{7}{4})}$
$tan (9) = \frac{ \frac{h}{40}}{ \frac{7h +650}{160}} = \frac{4h}{7h+650}$
$h = \frac{650 tan(9)}{4-7 tan(9)}$
$h = 35.6$

7 0

3 years ago