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mr Goodwill [35]
3 years ago
12

when 200. milliliters of an HNO3 solution is exactly neutralized by 250 milliliters of a 0.50 M solution of KOH, what is the con

centration of HNO3
Chemistry
1 answer:
marishachu [46]3 years ago
7 0

Answer:

Molarity HNO₃ Soln = 0.625M

Explanation:

Molarity of Acid Soln X Volume Acid Soln = Molarity of Base Soln x Volume of Base Soln

Molarity HNO₃ Soln x 200-ml HNO₃ Soln = 0.50M KOH Soln x 250-ml KOH Soln

Molarity HNO₃ Soln = (0.50M)(250ml)/(200ml) = 0.625M

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4.45 kcal of heat was added to increase the temperature of a sample of water from 23.0 °C to 57.8 °C. Calculate
Alona [7]

Answer:

m = 4450 g

Explanation:

Given data:

Amount of heat added = 4.45 Kcal ( 4.45 kcal ×1000 cal/ 1kcal = 4450 cal)

Initial temperature = 23.0°C

Final temperature = 57.8°C

Specific heat capacity of water = 1 cal/g.°C

Mass of water in gram = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 57.8°C - 23.0°C

ΔT = 34.8°C

4450 cal = m × 1 cal/g.°C × 34.8°C

m = 4450 cal / 1 cal/g

m = 4450 g

4 0
3 years ago
What is the purpose of adding phenolphthalein to your Erlenmeyer flask prior to starting a titration?
koban [17]

Answer:

a. The phenolphthalein acts as a color changing indicator to signal the endpoint of the reaction.

Explanation:

Phenolphthalein is an organic substance with chemical formula C_{20}H_{14}O_{4}.

It is a substance commonly used in acid-base titrations to indicate the end point in the titration because phenolphthalein is colorless in acidic solutions but turns a purplish-pink color in basic solutions.

In this way it helps visually to notice when the final point of the titration has been reached.

3 0
3 years ago
Which type of structure do most ionic compounds form
Setler79 [48]

Answer: crystalline solid

Explanation: Most ionic compounds exist in crystalline solid form especially at room temperature.

4 0
3 years ago
Can I find the state of Ca3N2 using the solubility rules? If so how because there is no Nitride in the solubility tables, I don'
Mamont248 [21]

Answer:

The day I was in the shower and I will be there at remove the day I was in the shower and I will be there at remove the day to see if you have any questions please feel free to contacts and the day I was in the shower and I will be there at remove the day I was in the shower and I will be there at remove the days of the week are you

8 0
3 years ago
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A 34.0 g piece of metal is heated to 92.0°C then placed in a beaker of water containing 22.0 g of water at 19.0°C. The temperatu
lapo4ka [179]

Answer:

0.1988 J/g°C

Explanation:

-Qmetal = Qwater

Q = mc∆T

Where;

Q = amount of heat

m = mass of substance

c = specific heat of substance

∆T = change in temperature

Hence;

-{mc∆T} of metal = {mc∆T} of water

From the information provided in this question, For water; m= 22.0g, ∆T = (24°C-19°C), c = 4.18J/g°C.

For metal; m= 34.0g, ∆T = (24°C-92°C), c = ?

Note that, the final temperature of water and the metal = 24°C

-{34 × c × (24°C-92°C)} = 22 × 4.18 × (24°C-19°C)

-{34 × c × (-68°C)} = 459.8

-{34 × c × -68} = 459.8

-{-2312c} = 459.8

+2312c = 459.8

c = 459.8/2312

c = 0.1988

The specific heat capacity of the metal is 0.1988 J/g°C

6 0
3 years ago
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