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mr Goodwill [35]
3 years ago
12

when 200. milliliters of an HNO3 solution is exactly neutralized by 250 milliliters of a 0.50 M solution of KOH, what is the con

centration of HNO3
Chemistry
1 answer:
marishachu [46]3 years ago
7 0

Answer:

Molarity HNO₃ Soln = 0.625M

Explanation:

Molarity of Acid Soln X Volume Acid Soln = Molarity of Base Soln x Volume of Base Soln

Molarity HNO₃ Soln x 200-ml HNO₃ Soln = 0.50M KOH Soln x 250-ml KOH Soln

Molarity HNO₃ Soln = (0.50M)(250ml)/(200ml) = 0.625M

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Determine the volume of a substance that has a density of 1.84 g/ml and a mass of 12 grams
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Hey there!:

density = mass / volume

1.84 g/mL =  12 g / V

V =  12 / 1.84

V = 6.521 mL

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3 years ago
A volume of 90.0 mL of aqueous potassium hydroxide (KOH) was titrated against a standard solution of sulfuric acid (H2SO4). What
Gemiola [76]

Answer:

The answer to your question:  0.7 M

Explanation:

Data

V of KOH = 90 ml

[KOH] = ?

V H2SO4 = 21.2 ml

[H2SO4] = 1.5 M

                       2KOH(aq)  +  H₂SO₄(aq)   →   K₂SO₄(aq)  +  2H₂O(l)

Molarity = moles / volume

moles of H₂SO₄ = (1.5) (21.2)

                           = 31.8

                    2 moles of KOH --------------  1 mol of H₂SO₄

                   x                           --------------  31.8 mol of H₂SO₄

                    x = (31.8)(2) / 1

                    x = 63.8 moles of KOH

Molarity = 63.8 / 90

             = 0.7 M

7 0
2 years ago
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