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defon
3 years ago
10

3.01x10^15 atoms of S= g

Chemistry
1 answer:
astra-53 [7]3 years ago
4 0

There are 1.65 × 10^(-7) g S in 3.01 × 10^15 atoms S.

<em>Step 1</em>. Use Avogadro’s number to convert <em>atoms of S to moles of S</em>

Moles of S = 3.01 × 10^15 atoms S × (1 mol S/6.022 × 10^23 atoms S)

= 5.148 × 10^(-9) mol S

<em>Step 2</em>. Use the molar mass of S to convert <em>moles of S to grams of S </em>

Mass of S = 5.148 × 10^(-9) mol S × (32.06 g S/1 mol S) = 1.65 × 10^(-7) g S

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n = 6.02 \times 10^{25} \text{ molecules} \times \dfrac{\text{1 mol}}{6.022 \times 10^{23}\text{ molecules}} = \text{100.0 mol}

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3. Mass of CCl₄

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4. Volume of CCl₄

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