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Alik [6]
3 years ago
12

Some liquid will be poured from a 16 ounce container until it is filled to the percent of the the larger container (87.5%).How m

any ounces of liquid must be poured from to reach the full 16 ounce container?
Mathematics
1 answer:
4vir4ik [10]3 years ago
8 0

Answer:

16 ounces

Step-by-step explanation:

First we are told that a container has a capacity of 16 ounces of liquid and therefore 16 ounces of liquid can fill that one container

The 16 ounces liquid from the 16 ounce container is fully emptied in a larger container and fills 87.5% of the larger container therefore the larger container is:

100/87.5×16 ounces= 18.285 ounces in liquid capacity

Therefore to fill the smaller 16 ounce container, the larger container would have to pour 16 ounces of liquid into the smaller container, and would would still have 18.285-16=2.285 ounces if it(the larger container) were filled to the brim(100%)

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If the Mara family drives to Alexandria at a speed of 57 miles per hour, how many miles do they drive in 90 minutes? (Recall: 1
Anettt [7]
The answer is A. 1.5 Hours * 57 = 85.5
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4 years ago
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What is the equation of the line with slope of ½ , and which passes through the point <br> (4, - 5)?
Cerrena [4.2K]

Answer:

y = 1/2x - 7

Step-by-step explanation:

y = mx + b

m (slope) = 1/2

x = 4

y = -5

<em>substitute</em>

-5 = 1/2 * 4 + b

-5 = 2 + b

-5 -2 = b

-7 = b

y = mx + b

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8 0
3 years ago
Let ρ = x3 + xe−x for x ∈ (0, 1), compute the center of mass.
hram777 [196]

The center of mass is mathematically given as

\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}

<h3>What is the center of mass.?</h3>

Determine the center of mass in one dimension:

Represent the masses at the respective distances.

\begin{|c|c|} Masses \ & \ \ \ \ \ \ \ \ \ \ \ \ \ \ Located at \\\rho=x^{3}+x \cdot e^{-x} & \ \  \ \  x \in(0,1)$ \\\end

We calculate the total mass of the system.

\begin{aligned}m &=\int_{0}^{1} \rho \cdot d x \\& m =\int_{0}^{1}\left(x^{3}+x \cdot e^{-x}\right) \cdot d x \\&m =\left|\frac{x^{4}}{4}-(x+1) e^{-x}\right|_{0}^{1} \\&m =\left(\frac{5}{4}-\frac{2}{e}\right)\end{aligned}

Step 03: Calculate the moment of the system.

\begin{aligned}M &=\int_{0}^{1}(\rho \cdot x) \cdot d x \\& M=\int_{0}^{1}\left(x^{4}+x^{2} \cdot e^{-x}\right) \cdot d x \\&M =\left|\frac{x^{5}}{5}-\left(x^{2}-2 x+2\right) \cdot e^{-x}\right|_{0}^{1} \\&M=\left(\frac{11}{5}-\frac{5}{e}\right)\end{aligned}

we calculate the center of mass.

\begin{aligned}\bar{x} &=\left(\frac{M}{m}\right) \\& \bar{x}=\left\{\left(\frac{\left.11-\frac{5}{5}\right)}{\left(\frac{5}{4}-\frac{2}{e}\right)}\right\}\right.\\& \bar{x}=\left(\frac{11 e-25}{5 e}\right) \cdot\left(\frac{4 e}{5 e-8}\right) \\&\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}

Read more about the center of mass.

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8 0
2 years ago
Ana drinks chocolate milk out of glasses that each hold 1/8 of a liter
maxonik [38]

Answer:

5 3/5

Step-by-step explanation:

Convert 1/8 to 10/80 and 7/10 to 56/80 56/10= 5 3/5

7 0
3 years ago
Find the product of 2x2 + 3x - 6 and 4x3 - x + 7.​
yanalaym [24]

Answer:

8x^5 + 12x^4 - 26^3 + 11x^2 + 27x - 42

Step-by-step explanation:

(2x^2 + 3x - 6)(4x^3 - x + 7)

8x^5 -2x^3 +14x^2 + 12x^4 - 3x^2 + 21x -24x^3 + 6x - 42

8x^5 + 12x^4 - 26^3 + 11x^2 + 27x - 42

5 0
3 years ago
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