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Alik [6]
3 years ago
12

Some liquid will be poured from a 16 ounce container until it is filled to the percent of the the larger container (87.5%).How m

any ounces of liquid must be poured from to reach the full 16 ounce container?
Mathematics
1 answer:
4vir4ik [10]3 years ago
8 0

Answer:

16 ounces

Step-by-step explanation:

First we are told that a container has a capacity of 16 ounces of liquid and therefore 16 ounces of liquid can fill that one container

The 16 ounces liquid from the 16 ounce container is fully emptied in a larger container and fills 87.5% of the larger container therefore the larger container is:

100/87.5×16 ounces= 18.285 ounces in liquid capacity

Therefore to fill the smaller 16 ounce container, the larger container would have to pour 16 ounces of liquid into the smaller container, and would would still have 18.285-16=2.285 ounces if it(the larger container) were filled to the brim(100%)

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goblinko [34]

Answer:

6/5

Step-by-step explanation:

8 0
2 years ago
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10 (4p - 2k)(3)<br> In distributive property?
NeTakaya

Answer:

10 ( 12p - 6k)

Step-by-step explanation:

4p x 3 = 12p

2k x 3 = 6k

you cannot subtract 12p and 6k bcuz they do not have the same variables.

5 0
2 years ago
The prior probabilities for events A1 and A2 are P(A1) = 0.35 and P(A2) = 0.50. It is also known that P(A1 ∩ A2) = 0. Suppose P(
forsale [732]

Answer:

Step-by-step explanation:

Hello!

Given the probabilities:

P(A₁)= 0.35

P(A₂)= 0.50

P(A₁∩A₂)= 0

P(BIA₁)= 0.20

P(BIA₂)= 0.05

a)

Two events are mutually exclusive when the occurrence of one of them prevents the occurrence of the other in one repetition of the trial, this means that both events cannot occur at the same time and therefore they'll intersection is void (and its probability zero)

Considering that P(A₁∩A₂)= 0, we can assume that both events are mutually exclusive.

b)

Considering that P(BIA)= \frac{P(AnB)}{P(A)} you can clear the intersection from the formula P(AnB)= P(B/A)*P(A) and apply it for the given events:

P(A_1nB)= P(B/A_1) * P(A_1)= 0.20*0.35= 0.07

P(A_2nB)= P(B/A_2)*P(A_2)= 0.05*0.50= 0.025

c)

The probability of "B" is marginal, to calculate it you have to add all intersections where it occurs:

P(B)= (A₁∩B) + P(A₂∩B)=  0.07 + 0.025= 0.095

d)

The Bayes' theorem states that:

P(Ai/B)= \frac{P(B/Ai)*P(A)}{P(B)}

Then:

P(A_1/B)= \frac{P(B/A_1)*P(A_1)}{P(B)}= \frac{0.20*0.35}{0.095}= 0.737 = 0.74

P(A_2/B)= \frac{P(B/A_2)*P(A_2)}{P(B)} = \frac{0.05*0.50}{0.095} = 0.26

I hope it helps!

5 0
2 years ago
Lungimea unei gradini de 78 m iar perimetrul este de 256 m.Afla latimea gradinii
Yuri [45]
Trebuie sa postezi la pagina care e in romineste
L= 78 si P=256
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256=2*78+2w
256=156+2w
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8 0
3 years ago
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The product of 5 and a number y
zysi [14]

Answer: 5y

Step-by-step explanation:

Product means the multiplication of, so taking the product of 5 and y we simply have;

5*y=5y

8 0
2 years ago
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