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JulijaS [17]
4 years ago
8

Help me with just ONE question. Please

Mathematics
1 answer:
Novay_Z [31]4 years ago
4 0
A) by completing the square... X^2-8x+16+20-16 = (x^2-4)^2 +20-16=(x^2-4)+4

B) Since the coefficient of x^2 is positive, it is a quadratic function which increases positively. You know that it will always be above the x axis and therefore positive since the vertex is at (4,4) and increasing
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Can someone help me plz​
alexandr1967 [171]

Answer:

B. & E.

Step-by-step explanation:

First, to find your slope, put your line into slope-intercept form.

y=mx+b\\

3x-4y=7\\-4y=-3x+7\\y=\frac{3}{4} x-\frac{7}{4}

Your slope is \frac{3}{4}.

Now, you can find the y-intercept of your parallel line by plugging your given point and your slope into point-slope form.

y-y1=m(x-x1)\\y-(-2)=\frac{3}{4} (x-(-4))\\y+2=\frac{3}{4} (x+4)\\y+2=\frac{3}{4} x+3\\y=\frac{3}{4} x+1

Your y-intercept is 1.

If you notice, answer choice E is equivalent to one of our steps in converting it to point-slope form. Therefore, E is one of your answers.

The equation of your parallel line is:

y=\frac{3}{4} x+1

B is also a correct answer.

If you put B into slope-intercept form, you get the following:

3x-4y=-4\\-4y=-3x-4\\y=\frac{3}{4} x+1

This, of course, is equivalent to the parallel line which we already found, so we know it is parallel.

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Answer:

Step-by-step explanation:

These statements are true

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answer

Step-by-step explanation:

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