Question

Please help! It's due soon.

Answer 1

Answer:

Because f(g(x)) = g(f(x)) = x, f and g are inverse functions.

Step-by-step explanation:

f(g(x)) = f($\frac{1}{4}\sqrt{x}$) = $16(\frac{1}{4}\sqrt{x} ) ^{2} = 16(\frac{1}{16}x)=x$

g(f(x)) = g $(16x^{2}) = \frac{1}{4}\sqrt{16x^{2} } = \frac{1}{4}(4x) = x$