Answer: 8x
2.9543127e+21xy
9x
Step-by-step explanation:
4x^2=16x 28x=28x 36=36 16x+28x-36 16+28=44-36=8x
125x^6= 30517578125x 27y^15= 2.9543127e+21 30517578125x-2.9543127e+21= 2.9543127e+21xy
4-7=3+x=3x 5-8=3+x=3x 3x * 3x= 9x
Answer:
3 digits to the left side
Step-by-step explanation:
The decimal point will move 3 digits to the left side when dividing a decimal by 10³.
The volume of the first cube is (5h^2)^3, while the volume of the second cube is (3k)^3, so their total volume is (5h^2)^3 + (3k)^3. We can use the special formula for factoring a sum of two cubes:
x^3 + y^3 = (x + y)(x^2 - xy + y^2)
(5h^2)^3 + (3k)^3 = (5h^2 + 3k)((5h^2)^2 - (5h^2)(3k) + (3k)^2)
= (5h^2 + 3k)(25h^4 - 15(h^2)(k) + 9k^2)
This is the second of the given choices.
Classic Algebra and its unnecessarily complicated sentence structure. As you may have probably known, Algebra has its own "vocabulary set".
"the length of a rectangle exceeds its width by 6 inches" -> length is 6 in. longer than width -> l= w + 6
Since we're solving for the length and width, let's give them each variables.
length = l = w+6
width = w
The next bit of information is "the area is 40 square inches"
Applying the formula for the area of a rectangle we can set up:
l x w = 40
replace "l", or length, with it's alternate value.
(w+6) x w = 40
distribute
+ 6w = 40
subtract 40 from both sides
+ 6w - 40 = 0
factor
(w - 4)(w + 10) = 0
solve for w
w= 4, or -10
So great, we have 2 values; which one do we choose? Since this problem is referring to lengths and inches, we will have to choose the positive value. There is not such thing as a negative distance in the real world.
We now have half of the problem solved: width. Now we just need to find the length which we can do but substituting it back into the original alternate value of l.
l = w + 6
w=4
l = 4 + 6 = 10
The length is 10 in. and the width is 4 in. Hope this helps!
Answer:
The radius of the Ferris wheel is 
Step-by-step explanation:
we know that
The circumference of a circle is equal to

we have

substitute

Solve for r
