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julia-pushkina [17]
3 years ago
10

Blake measures the lengths, in inches, of 10 insects. He records the lengths of the insects on this line plot. He adds the lengt

hs of the 3 longest insects.
Mathematics
1 answer:
ivanzaharov [21]3 years ago
7 0

Answer: 5 inches

Step-by-step explanation:

The x's denote the insects measured so the longest insects would be of lengths:

1³/₄ inch, 1³/₄ inch and 1¹/₂ inch.

Adding them together would require converting them to improper fractions first:

7/4, 7/4, 3/2

Pick a denominator that is both denominators' lowest common multiple = 4

Adding them:

Divide the LCM by the denominator of the fraction and multiply the result by the numerator:

= (7 + 7 + 6) / 4

= 20/4

= 5 inches

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djyliett [7]

Answer: 8x

2.9543127e+21xy

9x

Step-by-step explanation:

4x^2=16x     28x=28x     36=36      16x+28x-36   16+28=44-36=8x

125x^6= 30517578125x    27y^15= 2.9543127e+21                             30517578125x-2.9543127e+21= 2.9543127e+21xy

4-7=3+x=3x    5-8=3+x=3x   3x * 3x= 9x

7 0
3 years ago
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When dividing a decimal by 10³, how is the decimal point moved?
shtirl [24]

Answer:

3 digits to the left side

Step-by-step explanation:

The decimal point will move 3 digits to the left side when dividing a decimal by 10³.

8 0
2 years ago
WILL CHOOSE BRAINLIEST
fredd [130]
The volume of the first cube is (5h^2)^3, while the volume of the second cube is (3k)^3, so their total volume is (5h^2)^3 + (3k)^3. We can use the special formula for factoring a sum of two cubes:
x^3 + y^3 = (x + y)(x^2 - xy + y^2)
(5h^2)^3 + (3k)^3 = (5h^2 + 3k)((5h^2)^2 - (5h^2)(3k) + (3k)^2)
= (5h^2 + 3k)(25h^4 - 15(h^2)(k) + 9k^2)
This is the second of the given choices.
5 0
3 years ago
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the length of a rectangle exceeds its width by 6 inches and the area is 40 square inches. What are the length and width of the r
Lorico [155]

Classic Algebra and its unnecessarily complicated sentence structure. As you may have probably known, Algebra has its own "vocabulary set".


"the length of a rectangle exceeds its width by 6 inches" -> length is 6 in. longer than width -> l= w + 6


Since we're solving for the length and width, let's give them each variables.

length = l = w+6

width = w


The next bit of information is "the area is 40 square inches"

Applying the formula for the area of a rectangle we can set up:

l x w = 40

replace "l", or length, with it's alternate value.

(w+6) x w = 40

distribute

w^{2} + 6w = 40

subtract 40 from both sides

w^{2} + 6w - 40 = 0

factor

(w - 4)(w + 10) = 0

solve for w

w= 4, or -10


So great, we have 2 values; which one do we choose? Since this problem is referring to lengths and inches, we will have to choose the positive value. There is not such thing as a negative distance in the real world.


We now have half of the problem solved: width. Now we just need to find the length which we can do but substituting it back into the original alternate value of l.


l = w + 6

w=4

l = 4 + 6 = 10


The length is 10 in. and the width is 4 in. Hope this helps!

8 0
3 years ago
To the nearest foot, what is the radius of the Ferris wheel if you traveled 157 feet?
Alex777 [14]

Answer:

The radius of the Ferris wheel is 25\ ft

Step-by-step explanation:

we know that

The circumference of a circle is equal to

C=2\pi r

we have

C=157\ ft

substitute

157=2(3.14)r

Solve for r

r=157/6.28=25\ ft

5 0
3 years ago
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