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2 years ago

Will give brainliest answer

Mathematics

2 answers:

Temka [501]2 years ago

7 0

Answer:

x coordinate B

Step-by-step explanation:

cos is always x coordinates, and it is a 3pi/4 rotation

puteri [66]2 years ago

5 0

Give me brainliest I'm jk

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40 points urgent really need answer

Kipish [7]

$a_1=1\\a_2=1+4=5\\a_3=5+2\cdot4=5+8=13\\a_4=13+3\cdot4=13+12=25\\a_5=25+4\cdot4=25+16=41\\a_6=41+5\cdot4=41+20=61$

Answer: d. 25 + 16 = 41

6 0

3 years ago

URGENT PLEASE ANSWER QUICKLY!!!!!!!! (WILL MARK BRAINLYIST)

mina [271]

Answer:

for 10 people she makes 35$

for 20 people she makes 55$

for 30 people she makes 75$

and for 40 people she makes 95$

Step-by-step explanation:

just plug the number of people (10, 20, 30, 40) into the x in the equation.

3 0

3 years ago

Colin’s piano lesson is 45 minutes, or Three-fourths of an hour, long. If he practices 6 different songs and spends an equal amo

NikAS [45]

Answer:

Colin spends 1/8 of an hour practicing each song

Step-by-step explanation:

Colin's piano lesson is 3/4 of an hour, long.

In that period, he practices 6 different songs, spending an equal amount of time on each one.

This means that each song gets the sixth part of the lesson duration. The fraction that expresses that amount is:

$\displaystyle \frac{\frac{3}{4}}{6}=\frac{3}{24}=\frac{1}{8}$

Colin spends 1/8 of an hour practicing each song

5 0

3 years ago

Read 2 more answers

The angle θ 1 is located in Quadrant IV, and cos ⁡ ( θ 1 ) = 9/ 19 , theta, start subscript, 1, end subscript, right parenthesis

Firdavs [7]

Answer:

$sin\theta_1 = - \frac{2\sqrt{70}}{19}$

Step-by-step explanation:

We are given that $\theta_1$ is in fourth quadrant.

$cos\theta_1$ is always positive in 4th quadrant and

$sin\theta_1$ is always negative in 4th quadrant.

Also, we know the following identity about $sin\theta$ and $cos\theta$ :

$sin^2\theta + cos^2\theta = 1$

Using \theta_1 in place of \theta:

$sin^2\theta_1 + cos^2\theta_1 = 1$

We are given that $cos\theta_1 = \frac{9}{19}$

$\Rightarrow sin^2\theta_1 + \dfrac{9^2}{19^2} = 1\\\Rightarrow sin^2\theta_1 = 1 - \dfrac{81}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{361-81}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{280}{361}\\\Rightarrow sin\theta_1 = \sqrt{\dfrac{280}{361}}\\\Rightarrow sin\theta_1 = +\dfrac{2\sqrt{70}}{19}, -\dfrac{2\sqrt{70}}{19}$

$\theta_1$ is in 4th quadrant so $sin\theta_1$ is negative.

So, value of $sin\theta_1 = - \frac{2\sqrt{70}}{19}$

6 0

3 years ago

Copy and complete statement

irakobra [83]

Answer:

sqrt(64) > 5

Step-by-step explanation:

sqrt(64) = 8; therefore

sqrt(64) > 5

3 0

3 years ago