Answer:
Hope it helps DEAR
Explanation:
Each box in the Punnet square should have BbEe in them. Yes, all of them contain this possible offspring genotype.
Explanation:
A mouse with black fur and one with white fur are being bred. Black fur is BBEE and white fur is bbee. Hence, when listing them on the Punnet square, the genotypes will be heterozygous, since there are possible traits of each fur color
Answer:
50%
Explanation:
Let's assume that the allele "T" gives the normal phenotype while the recessive allele "t" imparts the disease and is lethal in homozygous condition. The genotype of each of the two carrier parents would be "Tt". A cross between Tt and Tt would give the progeny in the following genotype ratio=
Tt x Tt= 1/4 TT: 1/2 Tt: 1/4 tt
Therefore, 1/2 or 50% progeny would be the carrier for the Tay-Sachs disease.
