Q = mCpΔT —> Solve for Cp —> Cp = q/mΔT
q = -6700 J (negative because it released heat
m = 70 g
ΔT = Final temp - initial temp = 25 - 90 = -65°C
Cp = -6700 J / (70 g)(-65°C) = 1.47 J/g°C
The answer to that question would be C
Answer:
Reductio is gain of electrons, while oxdation is loss. The oxidtion states of carbon in the reaction will show either of oxidation or reduction occurrence.
→ 
Explanation:
Electrons displacement is explained for each reaction below:
- +2 to +4 = loss of 2 more lectrons-------oxidation
- +4 throughout reaction----no exchange of electrons
- -4 to +4 = loss of 4 electrons-----oxidation
- 0 to -2 = gain of 2 electrons-----reduction