Answer: pH of a 0.500 M 
solution is 1.82
Explanation:
cM 0 0
So dissociation constant will be:
Give c= 0.500 M and 
= ?
Putting in the values we get:
![[H^+]=c\times \alpha](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3Dc%5Ctimes%20%5Calpha)
![[H^+]=0.500\times 0.030=0.015](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D0.500%5Ctimes%200.030%3D0.015)
Also ![pH=-log[H^+]](https://tex.z-dn.net/?f=pH%3D-log%5BH%5E%2B%5D)
![pH=-log[0.015]=1.82](https://tex.z-dn.net/?f=pH%3D-log%5B0.015%5D%3D1.82)
Thus pH of a 0.500 M solution is 1.82
Answer:
Reduction
Explanation:
Reduction:
Reduction involve the gain of electron and oxidation number is decreased.
Mn⁺⁷ +3e⁻ → Mn⁴⁺
Mn gets three electrons , its oxidation state reduced from +7 to +4 so Mn gets reduced.
Examples:
Consider the following reactions.
4KI + 2CuCl₂ → 2CuI + I₂ + 4KCl
the oxidation state of copper is changed from +2 to +1 so copper get reduced.
CO + H₂O → CO₂ + H₂
the oxidation state of carbon is +2 on reactant side and on product side it becomes +4 so carbon get oxidized.
H₂S + 2NaOH → Na₂S + 2H₂O
The oxidation sate of sulfur is -2 on reactant side and in product side it is also -2 so it neither oxidized nor reduced.
In order to solve this, we have to know the density of acetone because it is the ratio of mass to volume. At a certain temperature and pressure, the density of a specific substance does not change. It is an intrinsic property of a substance with temperature and pressure dependence. Assuming this is in normal conditions, the density is equal to 0.784 g/mL. So, the volume would be equal to
Volume = Mass/Density
Volume = 7.66 g/0.784 g/mL = 9.77 mL
Wooahhhh pollution can affect the environment and urself pollited water can affect marine animals and can result them in extinction global warmning melts Antarctica and can cause floodigs and extinction there. This probably wont help but i just free styled lol
Goodluck
i think so.
i learned this recently and my textbook says that neutrons and protons are in the nucleus and electrons orbit around the nucleus. :)
i hope i was able to help
