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3 years ago

How many moles of sucrose (C12H22O11) would be in 8.7 L of a 1.1 M solution of sucrose?

Chemistry

1 answer:

poizon [28]3 years ago

5 0

Answer:

9.57 mol.

Explanation:

Molarity is defined as the no. of moles of a solute per 1.0 L of the solution.

M = (no. of moles of solute)/(V of the solution (L)).

∴ M = (no. of moles of sucrose)/(V of the solution (L)).

1.1 M = (no. of moles of sucrose)/(8.7 L).

∴ no. of moles of sucrose = (1.1 M)(8.7 L) = 9.57 mol.

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3 years ago

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tiny-mole [99]

Answer:

3AgCl + Na₃PO₄ —> 3NaCl + Ag₃PO₄

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Explanation:

From the question given above, the following data were:

Silver chloride reacts with sodium phosphate to yield sodium chloride and silver phosphate. This can be written as follow:

AgCl + Na₃PO₄ —> NaCl + Ag₃PO₄

The above equation can be balanced as follow:

AgCl + Na₃PO₄ —> NaCl + Ag₃PO₄

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6 0

3 years ago

Determine the number of moles of iodine that reacts with 50g of aluminum

frozen [14]

Answer: The correct answer is option B i.e., 2.78 mol

Explanation:

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$2Al(s)+3I_{2}(s) \to Al_{2}I_{6}(s)$

From the equation, it is clear that 3 moles of iodine reacts with 2 moles of Aluminium to form Aluminium iodide

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3 years ago

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Answer:

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