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Sladkaya [172]
3 years ago
12

How many moles of sucrose (C12H22O11) would be in 8.7 L of a 1.1 M solution of sucrose?

Chemistry
1 answer:
poizon [28]3 years ago
5 0

Answer:

9.57 mol.

Explanation:

<em>Molarity is defined as the no. of moles of a solute per 1.0 L of the solution.</em>

<em />

<em>M = (no. of moles of solute)/(V of the solution (L)).</em>

<em></em>

∴ M = (no. of moles of sucrose)/(V of the solution (L)).

1.1 M = (no. of moles of sucrose)/(8.7 L).

<em>∴ no. of moles of sucrose = (1.1 M)(8.7 L) = 9.57 mol.</em>

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If the flour mixture is then taken and put into the oven for about 20 minutes, it turns into something very tasty. What kind of
Margaret [11]

Answer:

physical change

Explanation:

i got the same question sorry for the late response but that's the answer good luck

7 0
3 years ago
The average dosage of oxcarbazepine for an epileptic child between the ages of 4 and 16 is 9.00 mgmg per 1 kgkg of body weight (
Helga [31]

Answer:

The answer to your question is 3 ml

Explanation:

Data

Dosage = 9.0 mg/ kg

Child's weight = 42.9 pounds

Suspension = 60 mg/ml

milliliters = ?

Process

1.- Convert the weight to kg

                         1 pound ------------------- 0.453 kg

                     42.9 pounds ---------------  x

                           x = (42.9 x 0.453) / 1

                           x = 19.43 kg

2.- Calculate the milligrams the child needs

                         1 kg of weight ------------ 9 mg

                       19.43 kg ----------------------  x

                            x = (19.43 x 9) / 1

                            x = 174.87 mg of oxcarbazepine

3.- Calculate the milliliters needed

                          60 mg of suspension ------------- 1 milliliters

                        174.87 mg                     --------------  x

                                 x = (174.87 x 1) / 60

                                 x = 2.9 ml ≈ 3 ml

5 0
3 years ago
A sample of an ideal gas has a volume of 2.21 L at 282 K and 1.03 atm. Calculate the pressure when the volume is 1.84 L
PIT_PIT [208]

Answer:

1.33 atm

Explanation:

use general gas equation P1 V1/ T1 = P2 V2/ T2

rearrange and make P2 the subject then solve,it should give you 1.33 atm

3 0
3 years ago
What is the mass of 0.251 moles of water? Using dimensional analysis show work
AVprozaik [17]

1 \text{ mol of H}_2 \text{O} \equiv 18 \text{ g} \implies 0.251  \text{ moles of H}_2 \text{O} \equiv 4.518 \text{ g}

3 0
3 years ago
After completing an experiment to determine gravimetrically the percentage of water in a hydrate, a student reported a value of
SIZIF [17.4K]

Answer:

b) The dehydrated sample absorbed moisture after heating

Explanation:

a) Strong initial heating caused some of the hydrate sample to splatter out.

This will result in a higher percent of water than the real one, because you assume in the calculation that the splattered sample was only water (which in not true).

b) The dehydrated sample absorbed moisture after heating.

Usually inorganic salts may absorbed moisture from the atmosphere so this will explain the 13% difference between calculated water percent the real content of water in the hydrate.

c) The amount of the hydrate sample used was too small.

It will create some errors but they do not create a difference of 13% difference as stated in the problem.

d) The crucible was not heated to constant mass before use.

Here the error is small.

e) Excess heating caused the dehydrated sample to decompose.

Usually the inorganic compounds are stable in the temperature range of this kind of experiments. If you have an organic compound which retain water molecules you may decompose the sample forming volatile compounds which will leave crucible so the error will be quite high.

6 0
3 years ago
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