How many moles of sucrose (C12H22O11) would be in 8.7 L of a 1.1 M solution of sucrose?
1 answer:
Answer:
9.57 mol.
Explanation:
<em>Molarity is defined as the no. of moles of a solute per 1.0 L of the solution.</em>
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<em>M = (no. of moles of solute)/(V of the solution (L)).</em>
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∴ M = (no. of moles of sucrose)/(V of the solution (L)).
1.1 M = (no. of moles of sucrose)/(8.7 L).
<em>∴ no. of moles of sucrose = (1.1 M)(8.7 L) = 9.57 mol.</em>
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