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natka813 [3]
3 years ago
5

For the reaction: h2(g) + cl2(g) → 2hcl(g), how many moles hcl will be produced from 10.0 g of h2? the reaction occurs in the pr

esence of excess cl2

Chemistry
2 answers:
Vesna [10]3 years ago
6 0

Answer : The moles of HCl produced will be, 10 moles

Explanation : Given,

Mass of H_2 = 10 g

Molar mass of H_2 = 2 g/mole

First we have to calculate the moles of H_2.

\text{Moles of }H_2=\frac{\text{Mass of }H_2}{\text{Molar mass of }H_2}=\frac{10g}{2g/mole}=5moles

Now we have to calculate to moles of HCl.

The given balanced chemical reaction is,

H_2(g)+Cl_2(g)\rightarrow 2HCl(g)

From the balanced chemical reaction, we conclude that

As, 1 mole of H_2 react to give 2 moles of HCl

So, 5 mole of H_2 react to give 2\times 5=10 moles of HCl

Therefore, the moles of HCl produced will be, 10 moles

motikmotik3 years ago
3 0
Hope this would help you

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The maximum efficiency possible in an energy conversion process that is not limited by the second law of thermodynamics
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Answer:

100 %

Explanation:

The maximun efficiency possible (whem not limited by the  second law of thermodynamics) happens when all the energy used is transformed into the type of energy we required with no other transformations.

For example, in an engine we want that all the energy we supply is being converted to work. That's the ideal case, but in reality always some of that energy is lost in the form of heat.

5 0
3 years ago
Cacl2+na3po4 ca3po42 + nacl
Alex787 [66]
<h3>Answer:</h3>

3CaCl₂ + 2Na₃PO₄→ Ca₃(PO₄)₂ + 6NaCl

<h3>Explanation:</h3>

We are given the Equation;

CaCl₂ + Na₃PO₄→ Ca₃(PO₄)₂ + NaCl

Assuming the question requires us to balance the equation;

  • A balanced chemical equation is one that has equal number of atoms of each element on both sides of the equation.
  • Balancing chemical equations ensures that they obey the law of conservation of mass in chemical equations.
  • According to the law of conservation of mass in chemical equation, the mass of the reactants should always be equal to the mass of the products.
  • Balancing chemical equations involves putting appropriate coefficients on the reactants and products.

In this case;

  • To balance the equation we are going to put the coefficients 3, 2, 1, and 6.
  • Therefore; the balanced equation will be;

3CaCl₂ + 2Na₃PO₄→ Ca₃(PO₄)₂ + 6NaCl

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3 years ago
Which line segment on the graph represents boiling
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1. There is no graph given

2. ENERGY LEVELS!!!

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3 years ago
Need help balancing equations please.
densk [106]

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Acetaminophen is the generic name of the pain reliever in Tylenol and some other headache remedies- The compoundhas the molecula
slega [8]

<u>Answer:</u> The mass percentage of carbon element is 63.57 %, hydrogen element is 5.96 %, nitrogen element is 9.28 % and oxygen element is 21.19 %

<u>Explanation:</u>

We are given:

A chemical compound having chemical formula of C_8H_9NO_2. This compound is made by the combination of carbon, hydrogen, nitrogen and oxygen elements.

1 mole of acetaminophen contains 8 moles of carbon atom, 9 moles of hydrogen atom, 1 mole of nitrogen atom and 2 moles of oxygen atom

Mass of carbon element = (8\times 12)=96g/mol

Mass of hydrogen element = (9\times 1)=9g/mol

Mass of nitrogen element = (1\times 14)=14g/mol

Mass of oxygen element = (2\times 16)=32g/mol

Mass of the compound = 151 g/mol

To calculate the percentage composition of an element in a compound, we use the equation:

\%\text{ composition of an element}=\frac{\text{Mass of element}}{\text{Mass of compound}}\times 100      ........(1)

  • <u>For carbon element:</u>

Putting values in equation 1, we get:

\% \text{ composition of carbon element}=\frac{96}{151}\times 100\\\\\% \text{ composition of carbon element}=63.57\%

  • <u>For hydrogen element:</u>

Putting values in equation 1, we get:

\% \text{ composition of hydrogen element}=\frac{9}{151}\times 100\\\\\% \text{ composition of hydrogen element}=5.96\%

  • <u>For nitrogen element:</u>

Putting values in equation 1, we get:

\% \text{ composition of nitrogen element}=\frac{14}{151}\times 100\\\\\% \text{ composition of nitrogen element}=9.28\%

  • <u>For oxygen element:</u>

Putting values in equation 1, we get:

\% \text{ composition of oxygen element}=\frac{32}{151}\times 100\\\\\% \text{ composition of oxygen element}=21.19\%

Hence, the mass percentage of carbon element is 63.57 %, hydrogen element is 5.96 %, nitrogen element is 9.28 % and oxygen element is 21.19 %

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