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3 years ago

15

Select all the expressions that represent the area of the large, outer rectangle. * 3 points Captionless Image 5(2 + 4) 5 x 2 +

4 5 x 2 + 5 x 4 5 x 2 x 4 5 x 6

2 answers:

erik [133]3 years ago

4 0

Step-by-step explanation:

121630....................................

Anton [14]3 years ago

3 0

Answer:

there isn't any pictur

Step-by-step explanation:

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There are 4 3/8 pounds of bricks in a bag. Each brick weighs 7/8 of a pound. How many bricks are in the bag?

goldfiish [28.3K]

Hello :) the answer to your question would be 5. There are 5 bricks in each bag. 35/8

7 0

2 years ago

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53x52 step by step plzzz

Zigmanuir [339]

Answer: here you go i tried my best

Step-by-step explanation:

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3 years ago

The corners of a meadow are shown on a coordinate grid. Ethan wants to fence the meadow. What length of fencing is required?

Nuetrik [128]

Answer:

34.6 units

Step-by-step explanation:

The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.

The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).

Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:

Distance between point A(-6, 2) and point B(2, 6):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$A(-6, 2)) = (x_1, y_1)$

$B(2, 6) = (x_2, y_2)$

$AB = \sqrt{(2 - (-6))^2 + (6 - 2)^2}$

$AB = \sqrt{(8)^2 + (4)^2}$

$AB = \sqrt{64 + 16} = \sqrt{80}$

$AB = 8.9$ (nearest tenth)

Distance between B(2, 6) and C(7, 1):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$B(2, 6) = (x_1, y_1)$

$C(7, 1) = (x_2, y_2)$

$BC = \sqrt{(7 - 2)^2 + (1 - 6)^2}$

$BC = \sqrt{(5)^2 + (-5)^2}$

$BC = \sqrt{25 + 25} = \sqrt{50}$

$BC = 7.1$ (nearest tenth)

Distance between C(7, 1) and D(3, -5):

$CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$C(7, 1) = (x_1, y_1)$

$D(3, -5) = (x_2, y_2)$

$CD = \sqrt{(3 - 7)^2 + (-5 - 1)^2}$

$CD = \sqrt{(-4)^2 + (-6)^2}$

$CD = \sqrt{16 + 36} = \sqrt{52}$

$CD = 7.2$ (nearest tenth)

Distance between D(3, -5) and A(-6, 2):

$DA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$D(3, -5) = (x_1, y_1)$

$A(-6, 2) = (x_2, y_2)$

$DA = \sqrt{(-6 - 3)^2 + (2 - (-5))^2}$

$DA = \sqrt{(-9)^2 + (7)^2}$

$DA = \sqrt{81 + 49} = \sqrt{130}$

$DA = 11.4$ (nearest tenth)

Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units

8 0

3 years ago

Simplify<br> (3m²n4)3<br> O 9m5 n?<br> O 9m6n12<br> O 27mn12<br> O 27mn?

Lana71 [14]

Answer:

(3m2n4)^3

Step-by-step explanation:

This deals with raising to a power.

(3m2 • (n4))3

m2 raised to the 3 rd power = m( 2 * 3 ) = m6

n4 raised to the 3 rd power = n( 4 * 3 ) = n12

7 0

3 years ago

The right triangle shown has angles X, Y, and Z and side lengths a, b, and

laiz [17]

So attached is a picture of the triangle you are talking about and listed under are the choices:

A.) Cos Z=b/c
B.) Sin X=c/b
C.) Tan X=b/a
<span>D.) Tan Z=a/b
</span>
The answer would then be B. SinX = c/b.

Just remember SOH CAH TOA:

Sinθ=  Opposite    Cosθ = Adjacent Tanθ= Opposite
Hypotenuse    Hypotenuse    Adjacent

Using the triangle in the scenario, you just need to identify which side is which.

Given m∠Z
Adjacent = b
Opposite = a
Hypotenuse = c

SinZ=  a      CosZ = b TanZ= a
c     c    b

Given m∠X:

Adjacent = b
Opposite = a
Hypotenuse = c

SinX= <u> b </u>     CosX =<span><u> a </u></span>   TanX=<span><u> b </u></span>
c     c a

So the answer is B.

Attached is a picture of how I assigned the sides depending on the angle used.

4 0

4 years ago