Cameron's current service charge of $0.95 per song, and the new service charge of $0.89 per song and $12 fee for joining, gives;
- Formula for finding the number of songs that makes the cost of both services the same is; 0.95•s = 12 + 0.89•s
- Computing the value of <em>s </em>that satisfies the above equation gives the number of songs at which the cost of both service is the same as 200 songs
- The interpretation is the the cost of either service is the same when 200 songs are downloaded
<h3>How can the equation that gives the required number of songs be found?</h3>
To Formulate
The charges for songs on the current music service is, C1 = 0.95•s
The charges for the new download service is, C2 = 12 + 0.89•s
Where the $12 is the joining fee
When the cost is the same for both service, we have;
C1 = C2
Which gives;
The equation to represent when the cost for both service is the same is therefore;
0.95•s = 12 + 0.89•s
Computing;
The number of songs that gives the same costs is therefore;
0.95•s = 12 + 0.89•s
12 = 0.95•s - 0.89•s = 0.06•s
s = 12 ÷ 0.06 = 200
- The number of songs at which the cost of each option will be the same is <em>s </em>= 200 songs
Interpreting the solution;
The interpretation is, the cost of songs downloaded on both service will be the same, when 200 songs are downloaded.
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If you miss her then yes you should text her
<h3>Jason bought 20 stamps of $0.41 each and 8 postcards of $0.26 each.</h3>
<em><u>Solution:</u></em>
Let stamps be s and postcards be p
Given that,
The number of stamps was 4 more than twice the number of postcards
s = 4 + 2p -------- eqn 1
Jason bought both 41-cent stamps and 26-cent postcards and spent $10.28
41 cent = $ 0.41
26 cent = $ 0.26
Therefore,
0.41s + 0.26p = 10.28 --------- eqn 2
Substitute eqn 1 in eqn 2
0.41(4 + 2p) + 0.26p = 10.28
1.64 + 0.82p + 0.26p = 10.28
1.08p = 10.28 - 1.64
1.08p = 8.64
Divide both sides by 1.08
p = 8
Substitute p = 8 in eqn 1
s = 4 + 2(8)
s = 4 + 16
s = 20
Thus Jason bought 20 stamps and 8 post cards
