So the first thing that happens here is that the triangle is rotated 90 degrees clockwise. This can be seen because it is rotated, then you also notice that the triangle is reflected across the y axis.
There's a lot of different approaches to this question, but the easiest one I see is this:
If a chord goes through the center of the circle, it is a diameter. That's 180 degrees we don't have to worry about. 47 is an inscribed angle, so we can multiply it by two to get 94 degrees. Subtract 94 from 180 to get 86.
See y? It's also an inscribed angle. To get it, we just take the 86 we just found for the remaining arc and divide by two.
The measure of y is 43.
Use both!
You want to minimize <em>P</em>, so differentiate <em>P</em> with respect to <em>x</em> and set the derivative equal to 0 and solve for any critical points.
<em>P</em> = 8/<em>x</em> + 2<em>x</em>
d<em>P</em>/d<em>x</em> = -8/<em>x</em>² + 2 = 0
8/<em>x</em>² = 2
<em>x</em>² = 8/2 = 4
<em>x</em> = ± √4 = ± 2
You can then use the second derivative to determine the concavity of <em>P</em>, and its sign at a given critical point decides whether it is a minimum or a maximum.
We have
d²<em>P</em>/d<em>x</em>² = 16/<em>x</em>³
When <em>x</em> = -2, the second derivative is negative, which means there's a relative maximum here.
When <em>x</em> = 2, the second derivative is positive, which means there's a relative minimum here.
So, <em>P</em> has a relative maximum value of 8/(-2) + 2(-2) = -8 when <em>x</em> = -2.
14 adverage between numbers but i might be wrong
58b8 subtracting a negative is adding a positive
