2(4x-1) + 3(3-2x)=0
distribute
8x-2+9-6x=0
add like terms
2x+7=0
subtract 7 from both sides
2x= -7
divide both sides by 2
x=-7/2
X=-6
You get all the X to one side, and all the numbers to the other. Then divide. Work is shown in image below.
Answer:
x = ± sqrt(43)
Step-by-step explanation:
2x^2 - 28 = x^2 + 15
Subtract x^2 from each side
2x^2-x^2 - 28 = x^2-x^2 + 15
x^2 -28 = 15
Add 28 to each side
x^2 - 28 +28= 15+28
x^2 = 43
Take the square root of each side
sqrt(x^2) = ± sqrt(43)
x = ± sqrt(43)
When solving this equation you get x = -3.
To solve this, simply follow the order of operations for solving.
----> start by dividing both sides by 5
-----> Now you can transform the front side of the equation to use negative exponents.

Since both x and -3 are the powers of x, we can eliminate the 7 and just make the exponents equal.
-3 = x
Well, if we see the graph of x^2
the vertex is (0,0)
if we reflect it acrosss the x axis, teh vertex is still (0,0)
verteical strech doesn't change the vertex
vertex of g(x) is same as f(x)
first answer