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valina [46]
2 years ago
6

Two times x divide five

Mathematics
1 answer:
STALIN [3.7K]2 years ago
6 0

Answer:

2x/5

Step-by-step explanation:

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2(4x - 1) + 3(3 - 2x) = 0
LUCKY_DIMON [66]
2(4x-1) + 3(3-2x)=0
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8x-2+9-6x=0
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2x+7=0
subtract 7 from both sides
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3 0
3 years ago
Equation with Variables on both sides <br>8 + 4x = -10 + x with explanation please
stellarik [79]
X=-6

You get all the X to one side, and all the numbers to the other. Then divide. Work is shown in image below.

7 0
2 years ago
Solve!!!!! PLEASE HELP!!! MKE BRAINLIEST!<br> 2x^2 - 28 = x^2 + 15<br> What is the answer!
padilas [110]

Answer:

x =  ± sqrt(43)

Step-by-step explanation:

2x^2 - 28 = x^2 + 15

Subtract x^2 from each side

2x^2-x^2 - 28 = x^2-x^2 + 15

x^2 -28 = 15

Add 28 to each side

x^2 - 28 +28=  15+28

x^2 = 43

Take the square root of each side

sqrt(x^2) = ± sqrt(43)

x =  ± sqrt(43)

7 0
2 years ago
5/7^3 = 5(7^x)<br> Thank you for helping!!
SIZIF [17.4K]

When solving this equation you get x = -3.

To solve this, simply follow the order of operations for solving.

\frac{5}{7^{3}}  = 5(7^{x} ) ----> start by dividing both sides by 5

\frac{1}{7^{3}}  = (7^{x} ) -----> Now you can transform the front side of the equation to use negative exponents.

7^{-3} = 7^{x}

Since both x and -3 are the powers of x, we can eliminate the 7 and just make the exponents equal.

-3 = x

8 0
3 years ago
The function f(x) = x2 is reflected across the x-axis and a stretch factor of 4 is applied to create a second function, g(x). Wh
iren [92.7K]
Well, if we see the graph of x^2
the vertex is (0,0)
if we reflect it acrosss the x axis, teh vertex is still (0,0)
verteical strech doesn't change the vertex

vertex of g(x) is same as f(x)

first answer
7 0
3 years ago
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