Let us take 'a' in the place of 'y' so the equation becomes
(y+x) (ax+b)
Step-by-step explanation:
<u>Step 1:</u>
(a + x) (ax + b)
<u>Step 2: Proof</u>
Checking polynomial identity.
(ax+b )(x+a) = FOIL
(ax+b)(x+a)
ax^2+a^2x is the First Term in the FOIL
ax^2 + a^2x + bx + ab
(ax+b)(x+a)+bx+ab is the Second Term in the FOIL
Add both expressions together from First and Second Term
= ax^2 + a^2x + bx + ab
<u>Step 3: Proof
</u>
(ax+b)(x+a) = ax^2 + a^2x + bx + ab
Identity is Found
.
Trying with numbers now
(ax+b)(x+a) = ax^2 + a^2x + bx + ab
((2*5)+8)(5+2) =(2*5^2)+(2^2*5)+(8*5)+(2*8)
((10)+8)(7) =(2*25)+(4*5)+(40)+(16)
(18)(7) =(50)+(20)+(56)
126 =126
Interest depends a lot on the compounding period.
Since the period is exactly 4 months, we assume
APR=8%
monthly interest=8/12%=0.00666667
Interest due in 4 months
=7000[(1+0.08/12)^4-1]
=7000[0.0269345]
=$188.54
Six million, seven thousand and two hundred.
I think its true, i may be wrong tho.
Answer:
y=-sqrt(x^2+9)
Step-by-step explanation:
This problem can be solved with the help of separating the variables.
dy/dx=x/y
Multiply both sides by y
y dy/dx=x
Multiply both sides by dx
y dy=x dx
Integrate
y^2/2=x^2/2+c
Let's find c using the condition y(0)=-3.
(-3)^2/2=(0)^2/2+c
9/2=0+c
9/2=c.
The equation is y^2/2=x^2/2+9/2.
Let's make this a bit prettier multiplying both sides by 2:
y^2=x^2+9
Taking square root of both sides gives:
y=+/- sqrt(x^2+9)
Since we want y(0)=-3, then we will choose
y=-sqrt(x^2+9).
