Answer:
x=1
y=s
z=1
Step-by-step explanation:
(x, y, z)=(1, 0, 1)
Substitute 0 for y

Confirming if t=0 satisfy the other equation
x = e^−2t cos 4t = e^−2(0)cos(4*0)
= e^(0)cos(0) = 1
z = e^−2t = e^−2(0) = 0
Therefore t=0 satisfies the other equation
Finding the tangent vector at t=0

The vector equation of the tangent line is
(1, 0, 1) +s(0,1,0)= (1, s, 1)
The parametric equations are:
x=1
y=s
z=1
Answer:
x=58
Step-by-step explanation:
I think it's helps you
Answer:
y=1/2x-1
Step-by-step explanation:
-4y=4-2x
4y=4-2x
y=-1+1/2x
y=1/2x-1
Fill in m and n with numbers then minus by one