Given the mean of 15 of them is 18 and the mean of the rest is 13
And the total numbers are 25
So,
First, we need to find the sum of all numbers
the mean of 15 of them is 18
so, the sum of the 15 numbers are = 18 * 15 = 270
The rest of the numbers = 25 - 15 = 10
the mean of the rest is 13
so, the sum of the rest = 13 * 10 = 130
so, the sum of all numbers = 270 + 130 = 400
so, the mean of the all numbers =
So, the answer is, mean = 16
Answer:
144
Step-by-step explanation:
For a bitstring of length n, there are Fibonacci(n+2) strings containing no two consecutive zeros. This can be seen by constructing the strings starting with n=1.
1-bit strings: 1, 0 -- 2 strings not containing consecutive 0s
2-bit strings: 11, 10, 01 -- 3 strings not containing consecutive 0s
Note that we have added 1 to all the 1-bit strings, and added 0 only to the string ending in 1.
3-bit strings: 111, 110, 101, 011, 010 -- 5 strings not containing consecutive 0s
Note that these 5 strings consist of all (3) of the 2-bit strings with 1 appended, and all (1) of the 2-bit strings ending in 1 with 0 appended. The number that now end in 0 is the number previously ending in 1.
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If (x, y) represents the numbers of n-bit strings ending in (0, 1), then the number of (n+1)-bit strings ending in (0, 1) is (y, x+y). That is, the recursive relation is ...
For n=1 to n=10, these pairs are ...
(1, 1), (1, 2), (2, 3), (3, 5), (5, 8), (8, 13), (13, 21), (21, 34), (34, 55), (55, 89)
The sequence of b[n] values is ...
2, 3, 5, 8, 13, 21, 34, 55, 89, 144
which are the n=3 to n=12 numbers from the Fibonacci sequence.
That is, there will be Fibonacci(12) = 144 10-bit strings with no consecutive 0s.