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den301095 [7]
3 years ago
10

Victoria is going to a carnival that has games and rides. Each game costs $2 and each ride costs $4. Victoria spent $16 altogeth

er on 6 games and rides. Graphically solve a system of equations in order to determine the number of games Victoria played, x,x, and the number of rides Victoria went on, yy.
Mathematics
1 answer:
TiliK225 [7]3 years ago
8 0

Answer:

2 rides & 4 games

Step-by-step explanation:

2 rides=$8

4 games=$8

8+8=$16

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Luden [163]

Answer:

For a point defined bt a radius R, and an angle θ measured from the positive x-axis (like the one in the image)

The transformation to rectangular coordinates is written as:

x = R*cos(θ)

y = R*sin(θ)

Here we are in the unit circle, so we have a radius equal to 1, so R = 1.

Then the exact coordinates of the point are:

(cos(θ), sin(θ))

2) We want to mark a point Q in the unit circle sch that the tangent has a value of 0.

Remember that:

tan(x) = sin(x)/cos(x)

So if sin(x) = 0, then:

tan(x) = sin(x)/cos(x) = 0/cos(x) = 0

So tan(x) is 0 in the points such that the sine function is zero.

These values are:

sin(0°) = 0

sin(180°) = 0

Then the two possible points where the tangent is zero are the ones drawn in the image below.

7 0
3 years ago
Write a integer for the situation a deposit of $145.50<br> Helpppp fast pleaseeeee
-Dominant- [34]
11.64 is the integer
8 0
3 years ago
1. Two object accumulated a charge of
In-s [12.5K]

Answer:

The  magnitude of the electric force  between these two objects

will be: 181.274 N.

i.e.  F  =181.274 N

Step-by-step explanation:

As

Two object accumulated a charge of  4.5 μC and another a charge of 2.8  μC.

so

q₁ = 4.5 μC = 4.5 × 10⁻⁶ C

q₂ = 2.8  μC = 2.8 × 10⁻⁶  C

separated distance = d = 2.5 cm

Calculating the magnitude of the force between two charged objects using the formula:

F = \frac{1}{4\pi \epsilon_0}\frac{q_1 q_2}{r^2}

   =\:\frac{4.5\times \:\:10^{-6}\:\times \:\:2.8\:\times \:\:10^{-6}}{4\:\times \:\left(3.14\right)\:\times \:\left(8.85\times \:10^{-12}\right)\times \left(2.5\times \:\:10^{-2}\right)^2}

   =\frac{10^{-12}\times \:12.6}{10^{-12}\times \:4\times \:8.85\pi \left(10^{-2}\times \:2.5\right)^2}        ∵ 4.5\times \:10^{-6}\times \:2.8\times \:10^{-6}=10^{-12}\times \:12.6

   =\frac{10^{-12}\times \:12.6}{10^{-12}\times \:35.4\pi \left(10^{-2}\times \:2.5\right)^2}    ∵ \mathrm{Multiply\:the\:numbers:}\:4\times \:8.85=35.4

\mathrm{Cancel\:the\:common\:factor:}\:10^{-12}

  =\frac{12.6}{35.4\pi \left(10^{-2}\times \:2.5\right)^2}

  =\frac{12.6}{0.025^2\times \:35.4\pi }        ∵ \left(10^{-2}\times \:2.5\right)^2=0.025^2

  =\frac{12.6}{0.022125\pi }        ∵ 35.4\pi\times 0.025^2=0.022125\pi

   =\frac{12.6}{0.06950 }

F  =181.274 N

Therefore, the  magnitude of the electric force  between these two objects will be: 181.274 N.

i.e.  F  =181.274 N

7 0
3 years ago
A ski lodge charges $26 per day for a pass and $1.50 for every ski lift ride. A second ski
malfutka [58]

Answer:

32=40

26=39

Step-by-step explanation:

8 0
3 years ago
The first discount on a camera was 18%. The second discount was 20%. After the two discounts the price became $328. What was the
Lelechka [254]

Answer:

500

Step-by-step explanation:

Let x be the original price

Take the first discount

x - 18 percent

x - .18x = new price

x( 1-.18)

x ( .82) = new price

Now we take a 20 percent discount

This is on the discounted price, use .82x

.82x - 20 percent= 2nd discounted price

.82x - .20(.82x)

.82x -.164x

.656x= 2nd discounted price

.656x = 328

Divide each side by.656

.656x/.656 = 328/.656

x =500

The original price was 500

6 0
3 years ago
Read 2 more answers
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