Initial velocity of the plane is Vo = 0.
acceleration a = 1.3 m/s2
total distance = 2.5 km = 2500m
time taken to reach 2.5 km with 1.3m/s^2 acceleration = t
S = Vo t + 0.5 a t^2
2500 = 0 + (0.5*1.3* t^2)
t^2 = 3846.15
t = 62 s
the maximum velocity plan can reach within 62 s is Vt
Vt = Vo + a t
Vt = 0 + (1.3*62)
Vt = 80.6 m/s
Since 80.6 m/s is greater than 75 m/s, plane can use this runway to takeoff with required speed.
Answer:
FV= 1,000*(1.12^n)
Step-by-step explanation:
Giving the following information:
Initial investment= $1,000
Increase rate= 12% = 0.12
We need to formulate an exponential equation to show the value in n years.
<u>To calculate the Future Value, we need to use the following formula:</u>
FV= PV*(1+i)^n
Being:
FV= Future Value
PV= Initial Investment
i= increase rate
n= number of periods
FV= 1,000*(1.12^n)
<u>For example, for one year:</u>
FV= 1,000*(1.12^1)
FV= $1,120
For 3 years:
FV= 1,000*(1.12^3)
FV= $1,404.93
Answer:
((2^(-2))÷(3^3))^4=
Step-by-step explanation: expand
Answer:
x= -4, -3, 3
Step-by-step explanation:
You must factor this equation.
Once you factor, you get (x+4)(x-3)(x+3)
Set this equal to 0 and solve.
You get -4,-3, and 3.
Answer:
63
Step-by-step explanation:
