Answer:
A=5 hope this works
Step-by-step explanation:
Answer: The answer is C. $20.00
Step-by-step explanation:
Question 1:
For that point where all the lines intersect to be an incenter, the following must be true
4x - 1 = 6x - 5
Subtract both sides by 6x
-2x -1 = -5
Add both sides by 1
-2x = -4
Divide both sides by -2
x= 2
Question 2:
Plug in x=2 into any of the two equations.
You get 7.
Have an awesome day! :)
I think what you are looking for is 5x=300 therefore x=60 so at 60cars he would start to make more.
Answer:
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10th
Maths
Pair of Linear Equations in Two Variables
Algebraic Solution of a Pair of Linear Equations
Solve: 3x + 4y = 10,2x - 2y...
MATHS
Asked on December 27, 2019 byShweta Rudravaram
Solve: 3x+4y=10,2x−2y=2 by the method of elimination.
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ANSWER
3x+4y=10 …………..(1)
2x−2y=2 (or) x−y=1 …………(2)
(1) ⇒(3x+4y=10)1
(2) ⇒(x−y=1)3
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3x+4y=10
3x−3y=3
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7y=7
∴y=1
Put y=1 in (1) we get 3x+4×1=10
3x=10−4=6
∴x=36=2
Hence x=2,y=1.