Ask question

Ask question

All categories

Genrish500 [490]

1 year ago

7

Professor Torres is stucked in a burning building. He is leaning to the window on the 5th floor which is 60feets above the groun

d. For stability, the firefighter have to place the bottom of their ladder 15feet from the wall of the building. How long does the ladder needs to be to reach the window on the 5th floor and save professor Torres? round to 2 decimal place

1 answer:

denis-greek [22]1 year ago

3 0

The situation forms the right triangle above:

Where x is the length of the ladder.

Apply the Pythagorean theorem:

c^2 = a^2 +b^1

where:

c = hypotenuse = longest side = x

A &b = the other 2 legs of the triangle

Replacing:

x^2 = 60^2 + 15^2

Solve for x

x^2 = 3,600 + 225

x^2 = 3,825

x =√3,825

x = 61.85 ft

You might be interested in

What is the value of the x-coordinate of the vertex of the function shown

lakkis [162]

The answer is x=-2

As you could see, this is a factored function.

The un-factored version is x^2+4x-12

-b/2a=x

-4/2=-2= x of vertex

7 0

3 years ago

For brainiest:):):):):):):):)

Oksi-84 [34.3K]

Answer:

(a) 0.6

(b) 0.4

Step-by-step explanation:

If I am reading the little table right, You have made 9 shots, and have missed 6 of them. Therefore, in total, you have made $9+6=15$ shots.

The definition of probability is the number of events of a desired outcome divided by the total number of outcomes. Since you wish to make a shot for part a, the number of desired outcomes thus far is 9, out of 15 total shots. Thus,

$P($ making a shot $)=\frac{9}{15}=\frac{3}{5}=0.6$

Since making a shot and not making a shot are mutually exclusive events, and the only two events that could occur when shooting a basket, the probability of not making a shot and the probability of making a shot are all of the possible outcomes, and is thus equal to 1.

$P($ making a shot $)+P($ missing a shot) $=1$

$P($ missing a shot $)=1-P($ making a shot $)$

$P($ missing a shot $)=1-0.6=0.4$

QED

3 0

3 years ago

Lamaj is rides his bike over a piece of gum and continues riding his bike at a constant rate time = 1.25 seconds the game is at

Hitman42 [59]

Lamaj rides his bike over a piece of gum and continues riding his bike at a constant rate. At time = 1.25 seconds, the gum is at a maximum height above the ground and 1 second later the gum is on the ground again.

a. If the diameter of the wheel is 68 cm, write an equation that models the height of the gum in centimeters above the ground at any time, t, in seconds.

b. What is the height of the gum when Lamaj gets to the end of the block at t = 15.6 seconds?

c. When are the first and second times the gum reaches a height of 12 cm?

Answer:

Step-by-step explanation:

a)

We are being told that:

Lamaj rides his bike over a piece of gum and continues riding his bike at a constant rate. This keeps the wheel of his bike in Simple Harmonic Motion and the Trigonometric equation that models the height of the gum in centimeters above the ground at any time, t, in seconds. can be written as:

$\mathbf {y = 34cos (\pi (t-1.25))+34}$

where;

y = is the height of the gum at a given time (t) seconds

34 = amplitude of the motion

the amplitude of the motion was obtained by finding the middle between the highest and lowest point on the cosine graph.

$\mathbf{ \pi}$ = the period of the graph

1.25 = maximum vertical height stretched by 1.25 m to the horizontal

b) From the equation derived above;

if we replace t with 1.56 seconds ; we can determine the height of the gum when Lamaj gets to the end of the block .

So;

$\mathbf {y = 34cos (\pi (15.6-1.25))+34}$

$\mathbf {y = 34cos (\pi (14.35))+34}$

$\mathbf {y = 34cos (45.08)+34}$

$\mathbf{y = 58.01}$

Thus, the gum is at 58.01 cm from the ground at t = 15.6 seconds.

c)

When are the first and second times the gum reaches a height of 12 cm

This indicates the position of y; so y = 12 cm

From the same equation from (a); we have :

$\mathbf {y = 34 cos(\pi (t-1.25))+34}$

$\mathbf{12 = 34 cos ( \pi(t-1.25))+34}$

$\dfrac {12-34}{34} = cos (\pi(t-1.25))$

$\dfrac {-22}{34} = cos(\pi(t-1.25))$

$2.27 = (\pi (t-1.25)$

t = 2.72 seconds

Similarly, replacing cosine in the above equation with sine; we have:

$\mathbf {y = 34 sin (\pi (t-1.25))+34}$

$\mathbf{12 = 34 sin ( \pi(t-1.25))+34}$

$\dfrac {12-34}{34} = sin (\pi(t-1.25))$

$\dfrac {-22}{34} = sin (\pi(t-1.25))$

$-0.703 = (\pi(t-1.25))$

t = 2.527 seconds

Hence, the gum will reach 12 cm first at 2.527 sec and second time at 2.72 sec.

7 0

3 years ago

Yall are doing great thanks sm for the help

blondinia [14]

Answer:

That is an obtuse isosceles

4 0

3 years ago

The formula for the volume of a cube is V(s) = s3 where s is the side length of the cube. In which quadrant(s) is the graph of t

iVinArrow [24]

The answer is D because the function is a cubic function. if you graph for example, x³, it would be in Q. 1 and 3

5 0

3 years ago

Read 2 more answers