Answer:
Before the equivalence point, conductivity is decreasing. After the equivalence point, conductivity is increasing
Explanation:
In solution H2SO3 produce H+ ions and SO3²⁻ ions. In the same way, NaOH produce Na⁺ and OH⁻ ions. The conductivity of a solution is directly proportional to the concentration of ions in a solution. During titration, you are adding more NaOH (That is, more Na⁺ and OH⁻ ions). But each moles of OH⁻ reacts with H⁺ ion producing H₂O. That means the moles of Na⁺ that you are adding = Moles of H⁺ are been consumed. The concentration of ions remains approximately constant. But, H⁺ ion conducts better than Na⁺ ion. That means before the equivalence point, conductivity is decreasing. But after the equivalence point you will add OH- ions in excess increasing ion concentration increasing the conductivity:
After equivalence point, conductivity is increasing.
Hydrogen gas
Explanation:
Expression:
CO₂ + H₂ → CO + H₂O
Hydrogen gas in this reaction is oxidized in the reaction.
In this manner, it is the reducing agent in the reaction.
A reducing agent is the specie in a chemical reaction that undergoes the process of oxidation.
It is marked by:
- Addition of oxygen to a specie
- Removal of hydrogen from a specie
- Loss of electron by an atom
- Increase in oxidation number
- Increase in number of electronegative atoms surrounding a specie.
Here we see that H₂ fits this criteria perfectly well.
CO₂ is the one reduced.
learn more:
Oxidizing agent brainly.com/question/5558762
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A sand castle was changed by the ocean waves would be slowly taken away by the waves and would just become a smooth mound of sand. If someone stomped on it then it would still have the same amount of sand as before but in a different shape.
Answer:
The answer to your question is 510.7 kJ
Explanation:
Data
Q = ?
Volume = 2 L
Temperature 1 = T1 = 19°C
Temperature 2 = T2 = 80°C
Specific heat = 4.186 J/kg°C
Density of water = 1 g/ml
Equation
Q = mC(T2 - T1)
Process
1.- Calculate the mass of water
mass = density x volume
mass = 1 x 2000
mass = 2000 g
2.- Substitute values in the Heat formula
Q = (2000)(4.186)(80 - 19)
-Simplification
Q = (2000)(4.186)(61)
-Result
Q = 510692 J or 510.7 kJ