The energy of the 434 nm emission line is 4.58×10¯¹⁹ J (Option A)
<h3>Data obtained from the question </h3>
The following data were obtained from the question:
- Wavelength (λ) = 434 nm = 434×10¯⁹ m
- Planck's constant (h) = 6.626×10¯³⁴ Js
- Speed of light (v) = 3×10⁸ m/s
- Energy (E) =?
<h3>How to determine the energy </h3>
The energy of the 434 nm emission line can be obtained as follow:
E = hv / λ
E = (6.626×10¯³⁴ × 3×10⁸) / 434×10¯⁹ 9.58×10¹⁴
E = 4.58×10¯¹⁹ J
Thus, the energy of the 434 nm emission line is 4.58×10¯¹⁹ J
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In the reaction we gives the magnesium chloride and released hydrogen gas.
The reaction is carried out by contaning positive and negative charged on elements as follows
Mg + HCl --->MgCl2 + H2
Net reaction gives
Mg+ + 2Cl- + 2H+---> Mg+² + 2Cl- + 2H
Check it Mg(s) and Mg2+ not equal . The donor is element while the acceptor is an ion. The same process is done for H2 (g) and H+.
Answer:
the theory of plate tectonics
Explanation:
The theory of plate tectonics explains the formation and movement of the Earth's lithospheric plates. Major geographical events, such as earthquakes, volcanic eruptions, and mountain building, result from the movements of the lithospheric plates.