Most of the carbon is put away in sedimentary carbonates and kerogens, with the rest being spread between the sea, the air, biomass, for example, plants and creatures, and petroleum products.
<u>Explanation</u>:
- The carbon cycle is the procedure where carbon goes from the surrounding into living beings and to the Earth and then again goes into the air. Plants take carbon dioxide from the air and use it for food preparation. Creatures at that point eat the nourishment and carbon is put away in their bodies or discharged as CO2 through the breath.
- Most of the carbon is put away in sedimentary carbonates and kerogens, with the rest being spread between the sea, the air, biomass, for example, plants and creatures, and petroleum products. This is known as carbon storage.
- For instance, carbon, a fundamental component in natural particles, is preserved as it is moved from inorganic carbon in a biological system to natural atoms in living life forms of the biological system and back as inorganic carbon to the earth.
Answer:
$13,500
Explanation:
The differential analysis of the proposal to replace the commercial oven is shown below:-
The Total differential decrease in cost = Annual maintenance cost reduction × Number of years applicable
= $23,000 × 5
= $115,000
Inflow cash = The Total differential decrease in cost + Proceeds from sale of equipment
= 115,000 + $8,500
= $123,500
The Net differential decrease in cost from replacing equipment = Inflow cash - Cost of new equipment
= $123,500 - $110,000
= $13,500
Answer:
The eight protons in oxygen atom's nucleus will exert more force than nitrogen's seven electrons. Also, oxygen has same number of shells as nitrogen. Thus electrons in oxygen atom will be closer to nucleus than in the case of nitrogen. When electrons are closer it means atomic radius is smaller.
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Solution :
It is given that dilute hydrochloric acid is titrated with sodium carbonate solution.
of a 0.100 of hydrocholric acid is used.
Thus, 10 mL of the 0.1 molar dilute hydrochloric acid is titrated with 16.2 mL of Sodium carbonate solution.
The equation would be :
Now we know that that the
Molarity =
For hydrochloric acid solution,
∴ n = 0.01 moles.
Now for one mole of , two moles of HCl acid is used.
For one mole of HCl, one-half mole of is required.
Therefore, for 0.01 mole of HCl, we require 0.005 mole of .
Hence, 0.01 mole of hydrochloric acid and 0.005 mole of solution is used.
The color turns red when methyl orange indicator is used in HCl acid.