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mel-nik [20]
3 years ago
6

(Sugg eous equations. 3x + 2y = 12 4x – y = 5

Mathematics
1 answer:
Ostrovityanka [42]3 years ago
7 0

Answer:

1 × (3x + 2y = 12)

2 × (4x - y = 5)

3x + 2y = 12

+ (8x - 2y = 10)

= 11x = 22

divide both sides by the coefficient of 'x' (11)

Therefore x = 2

put (x = 2) in equation 1

3(2) + 2y = 12

6 + 2y = 12

2y = 12 - 6

2y = 6

divide both sides by the coefficient of 'y'(2)

Therefore y = 3

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iren [92.7K]

Answer:

The Supersmack gum has a volume of V=6.75\pi cm^3 or V=21.2057 cm^3. So, Supersmack's cylindrical bubble gum has more actual gum than the Megapop gumball

Step-by-step explanation:

Assuming that the radius of the Megapop gumball is 1.5 (the same diameter as Supersmack)

The volume of the cylinder's equation can be written as

V=\pi (1.5^{2})(3 )

This simplifies to

V=6.75\pi cm^3 or V=21.2057 cm^3

The volume of the gumball's equation can be written as

V=\frac{4}{3} \pi (1.5)^{3}

This simplifies to

v=4.5\pi cm^3 or V=14.1371 cm^3

The Supersmack gum has a volume of V=6.75\pi cm^3 or V=21.2057 cm^3. So, Supersmack's cylindrical bubble gum has more actual gum than the Megapop gumball

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4 years ago
Carol observes that all of the juniors are taking physics this year. She concludes that when she is a junior, she will take phys
Ulleksa [173]

Answer:

The answer is B.) Inductive Reasoning

Step-by-step explanation:

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6 0
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How many diggers where there when 50 were outside and 3 were in
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8 0
3 years ago
Read 2 more answers
The third and the sixth term of a geometric progression are 24 and 64/9 respectively. Find
Ratling [72]

Answer:

Ai. Common ratio = 2/3

Aii. First term = 54

B. Sum of the first five terms = 422/3

Step-by-step explanation:

From the question given above, the following data were obtained:

3rd term (T3) = 24

6Th term (T6) = 64/9

First term (a) =?

Common ratio (r) =?

Sum of the first five terms​ (S5) =?

Ai. Determination of the common ratio (r).

T3 = ar²

T3 = 24

24 = ar²....... (1)

T6 = ar⁵

T6 = 64/9

64/9 = ar⁵......... (2)

The equation are:

24 = ar²....... (1)

64/9 = ar⁵......... (2)

Divide equation 2 by equation 1.

64/9 ÷ 24 = ar⁵ / ar²

64/9 × 1/24 = r³

8/27 = r³

Take the cube root of both side

r = 3√(8/27)

r = 2/3

Thus, the common ratio is 2/3

Aii. Determination of the first term (a).

T3 = ar²

3rd term (T3) = 24

Common ratio (r) = 2/3

First term (a) =?

24 = a(2/3)²

24 = 4a/9

Cross multiply

24 × 9 = 4a

216 = 4a

Divide both side by 4

a = 216/4

a = 54

Thus, the first term (a) is 54

B. Determination of the sum of the first five terms.

Common ratio (r) = 2/3

First term (a) = 54

Number of term (n) = 5

Sum of first five terms (S5) =?

Sn = a[1 –rⁿ] / 1 – r

S5 = 54[1 – (⅔)⁵] / 1 – ⅔

S5 = 54 [1 – 32/243] / ⅓

S5 = 54 (211/243) × 3

S5 = 54 × 211/81

S5 = 6 × 211/9

S5 = 2 × 211/3

S5 = 422/3

Thus, the sum of the first five terms is 422/3

8 0
3 years ago
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