Using the fundamental counting theorem, we have that:
- 648 different area codes are possible with this rule.
- There are 6,480,000,000 possible 10-digit phone numbers.
- The amount of possible phone numbers is greater than 400,000,000, thus, there are enough possible phone numbers.
The fundamental counting principle states that if there are p ways to do a thing, and q ways to do another thing, and these two things are independent, there are ways to do both things.
For the area code:
- 8 options for the first digit.
- 9 options for the second and third.
Thus:

648 different area codes are possible with this rule.
For the number of 10-digit phone numbers:
- 7 digits, each with 10 options.
- 648 different area codes.
Then

There are 6,480,000,000 possible 10-digit phone numbers.
The amount of possible phone numbers is greater than 400,000,000, thus, there are enough possible phone numbers.
A similar problem is given at brainly.com/question/24067651
Answer:
For the first one use the formula
y=x*2
For the second use
y=x*4
The third is
y=x*15
The fourth is
y=x*16
Step-by-step explanation:
To find the value of the y units, u have to multiply any x unit with the first y unit given but not 0
idk if it makes sense but i tried
good luck!!
bahala kau ha ha. Matt wahak
Answer:
32
Step-by-step explanation:
We can write an algebraic equation to solve this situation:
, where x = first integer (small number) and x + 1 = the following integer.
Step 1: Combine like terms.
Step 2: Subtract 1 from both sides.
Step 3: Divide both sides by 2.
Therefore, the smaller number is 32 while the larger number is 33.
Have a lovely rest of your day/night, and good luck with your assignments! ♡