Answer: 49.85%
Step-by-step explanation:
Given : The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The distribution of the number of daily requests is bell-shaped ( normal distribution ) and has a mean of 61 and a standard deviation of 9.
i.e.
and 
To find : The approximate percentage of lightbulb replacement requests numbering between 34 and 61.
i.e. The approximate percentage of lightbulb replacement requests numbering between 34 and
.
i.e. i.e. The approximate percentage of lightbulb replacement requests numbering between
and
. (1)
According to the 68-95-99.7 rule, about 99.7% of the population lies within 3 standard deviations from the mean.
i.e. about 49.85% of the population lies below 3 standard deviations from mean and 49.85% of the population lies above 3 standard deviations from mean.
i.e.,The approximate percentage of lightbulb replacement requests numbering between
and
= 49.85%
⇒ The approximate percentage of lightbulb replacement requests numbering between 34 and 61.= 49.85%
Answer:
QF=gR
F=gR/Q
Step-by-step explanation:
Answer: The answer is 0.2
Step-by-step explanation: 2.4g / 12 minutes
0.2g/minutes
Answer:
10x - 2y
Step-by-step explanation:
<em>simplify</em><em> </em><em>the</em><em> </em><em>expression</em><em>.</em><em> </em>
<em>8x</em><em>–</em><em>2y</em><em> </em><em>+</em><em> </em><em>x</em><em> </em><em>+</em><em> </em><em>x</em><em> </em>
<em>combine</em><em> </em><em>numbers</em><em> </em><em>that</em><em> </em><em>have</em><em> </em><em>the</em><em> </em><em>same</em><em> </em><em>variables</em><em> </em>
<em>8x</em><em> </em><em>+</em><em> </em><em>x</em><em> </em><em>+</em><em> </em><em>x</em><em> </em>
<em>*</em><em>those</em><em> </em><em>x</em><em> </em><em>have</em><em> </em><em>1</em><em> </em><em>coefficient</em><em> </em><em>each</em><em>.</em><em> </em>
<em>it</em><em> </em><em>will</em><em> </em><em>be</em><em> </em><em>8x</em><em>+</em><em>1x</em><em>+</em><em>1x</em><em> </em><em>=</em><em> </em><em>10x</em><em> </em><em>then</em><em> </em><em>–</em><em>2y</em>
<em>10x</em><em>–</em><em>2y</em><em>.</em>
Hope it helps :)
It’s c because when you round your answer to 3 decimal places is equal to 16