Answer:
fulfillment management process
Explanation:
According to my research on the different business process', I can say that based on the information provided within the question this is best described as the fulfillment management process. Which is the process that a company goes through from accepting an order to delivering that order to the client. Which is what is happening in this situation.
I hope this answered your question. If you have any more questions feel free to ask away at Brainly.
Answer:
D. Software Problem
Explanation:
It could be that the software is bootlooping which will power on and off until its fixed.
Answer:
The first one
Explanation:
The other ones don’t make sense
Answer:
Internal and External Zones
Explanation:
Demilitarized Zone (DMZ) in a network means that, we make sure the security of network at higher level as military make sure the security of their bases or zones.
In this type of network, The network of the internal organization (LAN) needs security from hackers and unauthorized users who are trying to access the resources and information from the network.
This network is divided into two major zones. A DMZ has been placed between two zones along with firewalls enhance the security of LAN Network from the networks on internet. These two zones are named as Internal and External Zone. The firewall between DMZ and External zones monitors the users from external networks on the internet who tries to access organization's network. Internal network monitors the traffic between DMZ and Internal LAN network.
Answer:
Explanation:
The following code is written in Java and is a function/method that takes in an int array as a parameter. The type of array can be changed. The function then creates a counter and loops through each element in the array comparing each one, whenever one element is found to be a duplicate it increases the counter by 1 and moves on to the next element in the array. Finally, it prints out the number of duplicates.
public static int countDuplicate (int[] arr) {
int count = 0;
for(int i = 0; i < arr.length; i++) {
for(int j = i + 1; j < arr.length; j++) {
if(arr[i] == arr[j])
count++;
}
}
return count;
}
