We are asked to find for an expression that represents the perimeter of a picture frame which has a shape of a rectangle. The dimensions given are length of size x cm and a width of size 9 cm.
The formula for the Perimeter of a rectangle is given by
P=2L+2W
where L is the length and W is the width of the rectangle.
Hence,
P=2(x)+2(9)
Simplifying this values would give us a result of,
P=2x+18
Therefore, 2x+18 is the expression that represent the perimeter of the picture frame.
7. Four and 7 tenths
8. Twenty two and eighty nine hundredths
9. Forty Five and Three hundred Twenty Nine Thousandths
10.Twenty seven hundredths
Answer:
503
Step-by-step explanation:
Assuming I understand your question correctly, in that you’re looking for just some descriptions of the differences between the functions. If so, then I’d say:
First graph both functions, the f(x) and the g(x). Then spot the differences.
Note that the g(x) function has shifted towards the right compared with the f(x) function.
Another way that the g(x) differs from the f(x) function is that it’s stretched. The vertex is in the IV quadrant for g(x) rather than at the origin for f(x).
I hope that helps.
Answer:
Part 1) The trapezoid has an area of 
Part 2) The kite has an area of
Part 3) The area of the trapezoid is less than the area of the kite
Step-by-step explanation:
Part 1
Find the area of trapezoid
we know that
The area of trapezoid is equal to the area of two congruent triangles plus the area of a rectangle
so
![A=2[\frac{1}{2} (2)(5)]+(2)(5)](https://tex.z-dn.net/?f=A%3D2%5B%5Cfrac%7B1%7D%7B2%7D%20%282%29%285%29%5D%2B%282%29%285%29)
Part 2
Find the area of the kite
we know that
The area of the kite is equal to the area of two congruent triangles
so
![A=2[\frac{1}{2} (7)(3)]=21\ m^2](https://tex.z-dn.net/?f=A%3D2%5B%5Cfrac%7B1%7D%7B2%7D%20%287%29%283%29%5D%3D21%5C%20m%5E2)
Part 3
Compare the areas
The trapezoid has an area of 
The kite has an area of
so

therefore
The area of the trapezoid is less than the area of the kite